use*_*666 7 python if-statement list
我需要检查一个元素是否不在两个列表中.我目前有:
if ele not in lista:
if ele not in listb:
do stuff
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使用以下代码不起作用.有没有更有效的方法来完成上面的python?
if ele not in lista and listb:
do stuff
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jam*_*lak 17
if ele not in lista and ele not in listb:
# do stuff
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要么
if ele not in lista + listb:
# do stuff
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但第二个选项将涉及列表连接,这可能会导致大型列表的内存问题,它也必须两次通过列表.要解决这个问题,您可以使用itertools
:
from itertools import chain
if ele not in chain(lista, listb):
# do stuff
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如果您要不断检查成员资格,您希望使用set
具有O(1)
(分期)查找而不是O(n)
列表的查找.
例如.
items_set = set(chain(lista, listb))
if ele in items_set: # this membership check will be a lot faster
# do stuff
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