Ruby .split()正则表达式

Question

我正在尝试将字符串"[test| blah] [foo |bar][test|abc]"拆分为以下数组:

[
    ["test","blah"]
    ["foo","bar"]
    ["test","abc"]
]

但我无法正确表达我的正则表达式.

---

红宝石:

@test = '[test| blah] [foo |bar][test|abc]'.split(%r{\s*\]\s*\[\s*})
@test.each_with_index do |test, i|
  @test[i] = test.split(%r{\s*\|\s*})
end

我不在那里,这回来了:

[
    [ "[test" , "blah" ]
    [ "foo" , "bar" ]
    [ "test" , "abc]" ]
]

---

实现这一目标的正确正则表达式是什么？如果我还可以考虑新线路,那会很棒,比如说:"[test| blah] \n [foo |bar]\n[test|abc]"

Answer 1

最好String#scan用于此:

> "[test| blah] \n [foo |bar]\n[test|abc]".scan(/\[(.*?)\s*\|\s*(.*?)\]/)
=> [["test", "blah"], ["foo", "bar"], ["test", "abc"]]