使用地理编码器和Android Google Maps API v2获取经度和纬度

Ser*_*o76 23 maps android google-maps android-maps-v2

我正在使用Google Maps API v2 for android并且正常运行.但是,我正在尝试使用地理编码器来获取地址的经度和纬度,但没有成功.

它改变了从v2做到这一点的方式?

我正在使用传统的代码

Geocoder gc = new Geocoder(context);
//...
  List<Address> list = gc.getFromLocationName("1600 Amphitheatre Parkway, Mountain View, CA", 1);

  Address address = list.get(0);

  double lat = address.getLatitude();
  double lng = address.getLongitude();
//...
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始终返回强制关闭,Log不解决任何问题.当使用try/catch块时,打开地图但总是使用相同的位置使用Internet权限,我已经包含在项目中COARSE_LOCATION我已经使用了位于此处和其他站点的各种代码,但没有成功.

先感谢您.

Amo*_*uli 53

使用此示例url尝试此解决方案:

http://maps.google.com/maps/api/geocode/json?address=mumbai&sensor=false

它返回数据json与格式lat/lngaddress.

private class DataLongOperationAsynchTask extends AsyncTask<String, Void, String[]> {
   ProgressDialog dialog = new ProgressDialog(MainActivity.this);
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        dialog.setMessage("Please wait...");
        dialog.setCanceledOnTouchOutside(false);
        dialog.show();
    }

    @Override
    protected String[] doInBackground(String... params) {
        String response;
        try {
            response = getLatLongByURL("http://maps.google.com/maps/api/geocode/json?address=mumbai&sensor=false");
            Log.d("response",""+response);
            return new String[]{response};
        } catch (Exception e) {
            return new String[]{"error"};
        }
    }

    @Override
    protected void onPostExecute(String... result) {
        try {
            JSONObject jsonObject = new JSONObject(result[0]);

            double lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                    .getJSONObject("geometry").getJSONObject("location")
                    .getDouble("lng");

            double lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                    .getJSONObject("geometry").getJSONObject("location")
                    .getDouble("lat");

            Log.d("latitude", "" + lat);
            Log.d("longitude", "" + lng);
        } catch (JSONException e) {
            e.printStackTrace();
        }
        if (dialog.isShowing()) {
            dialog.dismiss();
        }
    }
}


public String getLatLongByURL(String requestURL) {
    URL url;
    String response = "";
    try {
        url = new URL(requestURL);

        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setReadTimeout(15000);
        conn.setConnectTimeout(15000);
        conn.setRequestMethod("GET");
        conn.setDoInput(true);
        conn.setRequestProperty("Content-Type",
                "application/x-www-form-urlencoded");
        conn.setDoOutput(true);
        int responseCode = conn.getResponseCode();

        if (responseCode == HttpsURLConnection.HTTP_OK) {
            String line;
            BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
            while ((line = br.readLine()) != null) {
                response += line;
            }
        } else {
            response = "";
        }

    } catch (Exception e) {
        e.printStackTrace();
    }
    return response;
}
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希望这会对你有所帮助.


Amo*_*uli 8

试试吧.

private void getLatLongFromAddress(String address)
{
    double lat= 0.0, lng= 0.0;

    Geocoder geoCoder = new Geocoder(this, Locale.getDefault());    
    try 
    {
        List<Address> addresses = geoCoder.getFromLocationName(address , 1);
        if (addresses.size() > 0) 
        {            
            GeoPoint p = new GeoPoint(
                    (int) (addresses.get(0).getLatitude() * 1E6), 
                    (int) (addresses.get(0).getLongitude() * 1E6));

            lat=p.getLatitudeE6()/1E6;
            lng=p.getLongitudeE6()/1E6;

            Log.d("Latitude", ""+lat);
            Log.d("Longitude", ""+lng);
        }
    }
    catch(Exception e)
    {
        e.printStackTrace();
    }
}
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