Dog*_*kci 1 python pep8 python-2.7
我应该如何分解这条线,以便它遵守PEP8?
assert (sum(map(lambda x: len(x),
(activities,apps,classes,users,verbs))) ==
Object.query
.filter(Object.status != ObjectStatusChoices.DELETED)
.count())
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如果将内容重写为单独的行,则永远不会出现.
它还允许您为中间值提供有意义的名称(我必须猜测,但可能您知道它们),或者甚至将逻辑位重构为函数(您也可以给出有意义的名称).
例如,不改变任何逻辑,甚至不改写任何逻辑(除了len
代替使用lambda x: len(x)
):
lengths = map(len, (activities,apps,classes,users,verbs))
db_query = Object.query.filter(Object.status != ObjectStatusChoices.DELETED)
assert sum(lengths) == db_query.count()
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