PHP MySQL查询其中x = $ variable

Question

我有这个代码(我知道电子邮件是定义的)

 <?php
$con=mysqli_connect($host,$user,$pass,$database);
 if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT `note` FROM `glogin_users` WHERE email = '.$email.'");

while($row = mysqli_fetch_array($result))
echo $row
?>

在我的MySQL数据库中,我有以下设置(表名是glogin_users)id电子邮件说明

我已经尝试从数据库中提取注释文本然后回显它但它似乎没有回应任何东西.

Answer 1

你现在正在做的是你添加.字符串而不是连接.它应该是,

$result = mysqli_query($con,"SELECT `note` FROM `glogin_users` WHERE email = '".$email."'");

或者干脆

$result = mysqli_query($con,"SELECT `note` FROM `glogin_users` WHERE email = '$email'");