Bra*_*rad 3 java substring while-loop
我正在为COSC课程制作的这个程序没有正确编译,我不断收到错误:
线程"main"中的异常java.lang.StringIndexOutOfBoundsException:字符串索引超出范围:2
在VowelCount.main的java.lang.String.substring(String.java:1765)(VowelCount.java:13)
这是我的代码:
import java.util.Scanner;
public class VowelCount {
public static void main(String[] args) {
int a = 0, e = 0, i = 0, o = 0, u = 0, count = 0;
String input, letter;
Scanner scan = new Scanner (System.in);
System.out.println ("Please enter a string: ");
input = scan.nextLine();
while (count <= input.length() ) {
letter = input.substring(count, (count + 1));
if (letter == "a") {
a++; }
if (letter == "e") {
e++; }
if (letter == "i") {
i++; }
if (letter == "o") {
o++; }
if (letter == "u") {
u++; }
count++;
}
System.out.println ("There are " + a + " a's.");
System.out.println ("There are " + e + " e's.");
System.out.println ("There are " + i + " i's.");
System.out.println ("There are " + o + " o's.");
System.out.println ("There are " + u + " u's.");
}
}
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据我所知,这应该有效,但为什么不呢?任何帮助都会很棒.谢谢!
您可能需要取出行中的=
while (count <= input.length() ) {
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并使它
while (count < input.length() ) {
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因为它导致子串读取超出字符串的长度.
===============但是我会添加一些额外的建议,即使它没有被要求:
不要使用==来比较字符串,使用
letter.equals("a")
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代替.或者甚至更好,尝试使用
char c = input.charAt(count);
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获取当前字符然后比较如下:
c == 'a'
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