Ruby数组一次访问2个连续(链接)元素

Question

现在,这是阵列,

[1,2,3,4,5,6,7,8,9]

我想要,

[1,2],[2,3],[3,4] upto [8,9]

当我这样做时,每个我都得到了(2),

[[1,2],[3,4]..[8,9]]

我目前这样做,

arr.each_with_index do |i,j|
  p [i,arr[j+1]].compact #During your arr.size is a odd number, remove nil.
end

有没有更好的办法？？

Answer 1

Ruby读你的想法.你想利弊 ecutive元素？

[1, 2, 3, 4, 5, 6, 7, 8, 9].each_cons(2).to_a
# => [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]]

Answer 2

.each_cons 完全符合你的要求.

[1] pry(main)> a = [1,2,3,4,5,6,7,8,9]
=> [1, 2, 3, 4, 5, 6, 7, 8, 9]
[2] pry(main)> a.each_cons(2).to_a
=> [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]]

Answer 3

你几乎做对了:)

arr = [1,2,3,4,5,6,7,8,9]
arr.each_cons(2) do |chunk|
  p chunk
end
# >> [1, 2]
# >> [2, 3]
# >> [3, 4]
# >> [4, 5]
# >> [5, 6]
# >> [6, 7]
# >> [7, 8]
# >> [8, 9]