4es*_*est 37 sql oracle select if-statement oracle10g
嗨,我只是选择并且工作得很好:
select 'CARAT Issue Open' issue_comment, i.issue_id, i.issue_status, i.issue_title, i.ISSUE_summary ,i.issue_description, i.severity,
gcrs.Area_name, gcrs.sector_name,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from table(f_carat_issues_as_of('31/MAR/2013')) i
inner join v_gcrs_with_stream gcrs on i.segment_id = gcrs.segment_id
where UPPER(ISSUE_STATUS) like '%OPEN%'
Run Code Online (Sandbox Code Playgroud)
现在我想调用两列:ISSUE_DIVISION和ISSUE_DIVISION_2
如果它们在新列中相等则应为值1,如果不相等则应为0,
我该怎么做 ?
我的完整代码:
select 'CARAT Issue Open' issue_comment, i.issue_id, i.issue_status, i.issue_title, i.ISSUE_summary ,i.issue_description, i.severity,
gcrs.Area_name, gcrs.sector_name,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from table(f_carat_issues_as_of('31/MAR/2013')) i
inner join v_gcrs_with_stream gcrs on i.segment_id = gcrs.segment_id
where UPPER(ISSUE_STATUS) like '%OPEN%' and
CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN
CASE WHEN ISSUE_DIVISION is null then "Null Value found"
Else 1 End
ELSE 0 END As Issue_Division_Result
Run Code Online (Sandbox Code Playgroud)
但是我得到了错误:ELSE 0 END As Issue_Division_Result
ORA-00920:无效的关系运算符:(
Art*_*Art 59
SELECT (CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN 1 ELSE 0 END) AS ISSUES
-- <add any columns to outer select from inner query>
FROM
( -- your query here --
select 'CARAT Issue Open' issue_comment, ...., ...,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from ....
where UPPER(ISSUE_STATUS) like '%OPEN%'
)
WHERE... -- optional --
Run Code Online (Sandbox Code Playgroud)
Dhi*_*kar 11
这么简单,你可以在这里使用case语句.
CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN
CASE WHEN ISSUE_DIVISION is null then "Null Value found" //give your option
Else 1 End
ELSE 0 END As Issue_Division_Result
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
305166 次 |
| 最近记录: |