Ruby从字符串中删除第一个单词

Question

我很难找到解决方案.如何从字符串中删除第一个单词,如下面的字符串.

     "i am going to school"

     "he is going to school"

     "she is going to school" 

     "they are going to school"

所以string可以是任何字符串,不知道第一个单词的确切长度.但只想删除第一个单词.

结果应如下所示

      "am going to school"

     "is going to school"

     "is going to school" 

     "are going to school"

有帮助吗？

谢谢

Answer 1

"i am going to school".split(' ')[1..-1].join(' ')

=> "am going to school"

你可以在ruby中的数组中使用两种方式,因此-1是最后一个元素.

或者切片,"我要上学".split('').drop(1).join('')`使用[Enumerable.drop](http://ruby-doc.org/core- 2.0/Enumerable.html#method-i-drop)跳过第一个元素. (5认同)

Answer 2

'she is going to school'[/(?<=\s).*/] => "is going to school"

这使用Ruby的积极lookbehind锚:

(？<= pat) - 正面的lookbehind断言:确保前面的字符匹配pat,但不包括匹配文本中的那些字符

因此,模式会查找空格字符,后跟任意字符串.由于重复(例如,"*")是贪婪的,它选择最长的匹配字符串.