在这篇文章之后,我发现了一些方法可以做到这一点,我希望得到它,我遇到了一些麻烦.这是我的代码:
var myDlg = $("#dlgpers"),lastsel;
myDlg.jqGrid({
url:'pers.php?id='+dataRow.id,
mtype:'GET',
datatype: "json",
ajaxGridOptions: { cache: false },
height:250,
cmTemplate: {sortable:false},
gridview: true,
cellEdit:true,
scroll:false,
colNames:['Id','Label','Information','Type','Data'],
colModel:[
{name:'id',index:'id',hidden:true,key:true},
{name:'label',index:'label',align:'right',width:100,editable:false,
cellattr: function (rowId, val, rawObject, cm, rdata) {
return ' style="font-weight:bold;margin-right:5px;border-left:0;border-top:0;" class="ui-state-active"' ;
}
},
{name:'info',index:'info',width:200,editable:true,edittype:'text'},
{name:'type',index:'type',width:30,hidden:true},
{name:'data',index:'data',width:30,hidden:true}
],
loadComplete: function () {
var rowIds = myDlg.jqGrid('getDataIDs');
$.each(rowIds, function (i, row) {
var rowData = myDlg.jqGrid('getRowData',row);
if (rowData.type == 'select') {
myDlg.jqGrid('restoreRow', row);
var cm = myDlg.jqGrid('getColProp', 'info');
cm.edittype = 'select';
cm.editoptions = { value: rowData.data };
myDlg.jqGrid('editRow', row);
cm.edittype = 'text';
cm.editoptions = null;
cm.editable = true;
}else{
myDlg.jqGrid('restoreRow', row);
var cm = myDlg.jqGrid('getColProp', 'info');
cm.edittype = 'text';
cm.editoptions = null;
cm.editable = true;
myDlg.jqGrid('editRow', row);
cm.edittype = 'text';
cm.editoptions = null;
cm.editable = true;
}
});
}
});
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和结果为图像:

和JSON响应:
{"page":1,"total":1,"records":1,"rows":[
{"cell":[0,"Nom ","LEBRUN","text",""]},
{"cell":[1,"Pr\u00e9nom ","Jacques","text",""]},
{"cell":[2,"Initiales ","LJ","text",""]},
{"cell":[3,"Fonction ","","text",""]},
{"cell"[4,"Service,"Administratif","select","0:Administratif;1:Commercial;2:Magasin;3:M\u00e9canique;4:Rejointage;5:Soudure;6:Tests"]},
{"cell":[5,"T\u00e9l\u00e9phone ","","text",""]},
{"cell":[6,"Email ","","text",""]},
{"cell":[7,"Statut ","CDI","select","0:CDI;1:CDD;2:App;3:Stg;4:Int"]},
{"cell":[8,"Entr\u00e9 le ","2008-10-06","text",""]},
{"cell":[9,"Sorti le ","0000-00-00","text",""]}]}
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我提交给您的两个问题:
非常感谢您帮助解决(并解释)我错误的方式.JiheL
更新2013-03-29
我已经应用了你的答案代码,运行正常!非常感谢.但是我为另一个主题创造了另一种形式,这给我带来了一些麻烦.
以下是此新表单的代码:
var showAbs=function(){
$('#EditDialog').empty();
var $table=$('<table></table>')
.attr('id','dlgcong')
.appendTo($('#EditDialog'));
var myCong = $("#dlgcong");
myCong.jqGrid({
url:'xpabs.php?id='+id+'&y='+y,
datatype: "json",
height:"auto",
cmTemplate: {sortable:false},
gridview: true,
colNames:['Type absence','Début','Fin','id'],
colModel:[
{name:'abs',index:'abs',width:155,editable:true,edittype:'select',
editoptions:{
dataUrl:"selabs.php",
dataEvents: [
{
type: 'change',
fn: function(e) {
$(this).parent().css('background-color','#'+$(this).find('option:selected').attr('colr'));
if($(this).find('option:selected').attr('colr')=='ffffff'){
$(this).parent().parent().find('input').datepicker('disable');
}else{
$(this).parent().parent().find('input').datepicker('enable');
$(this).parent().parent().attr('changed',true);
}
}
}
]
},
cellattr: function (rowId, val, rawObject, cm, rdata) {
return ' style="background-color:#'+rawObject[4]+';color:white;"';
}
},
{name:'debut',index:'debut',align:'center',width:70,editable:true},
{name:'fin',index:'fin',align:'center',width:70,editable:true},
{name:'id',index:'id',hidden:true}
],
jsonReader: {
cell: "",
root: function (obj) {
return obj;
}
},
loadComplete: function (data) {
var $self = $(this),
cm = $self.jqGrid("getColProp", "debut"),
idPrefix = $self.jqGrid("getGridParam", "idPrefix"),
l = data.length,
i,
item;
for (i = 0; i < l; i++) {
item = data[i];
cm.editoptions = {
dataInit: function(element) {
$(element).datepicker({
setDate:item[1],
minDate:'01/01/'+y,
maxDate:'31/12/'+y,
onSelect: function( selectedDate,inst ) {
$(element).val(selectedDate );
$(element).parent().parent().attr('changed',true);
}
})
}
}
}
var cm = $self.jqGrid("getColProp", "fin");
for (i = 0; i < l; i++) {
item = data[i];
cm.editoptions = {
dataInit: function(element) {
$(element).datepicker({
setDate:item[2],
minDate:'01/01/'+y,
maxDate:'31/12/'+y,
onSelect: function( selectedDate,inst ) {
$(element).val(selectedDate );
$(element).parent().parent().attr('changed',true);
}
})
}
}
$self.jqGrid("editRow", idPrefix + item[3]);
}
myCong.find('select').each(function(){
$(this).css({
backgroundColor:'transparent',
color:'white',
border:0,
width:155
});
});
},
idPrefix: "cong",
rowNum: 10000
});
//********************
// Button ' Valider '
//********************
$('<input />')
.attr({
type:'button',
})
.css({
float:'right',
marginTop:'5px'
})
.click(function(){
var toBeSaved='';
myCong.find('tr[changed=true]').each(function(idx){
if(toBeSaved.length>0){
toBeSaved+='|';
}
toBeSaved+=$(this).find('td:eq(3)').text()+';';
toBeSaved+=$(this).find('select option:selected').val()+';';
toBeSaved+=$(this).find('input:eq(0)').val()+';';
toBeSaved+=$(this).find('input:eq(1)').val();
});
if(toBeSaved.length>0){
$.ajax({
url:'majpabs.php?id='+id+'&data='+toBeSaved,
async:false,
dataType:'json',
success:function(data){
myGrid.trigger('reloadGrid');
$('#newAbs').val(' Nouveau ').attr('disabled',false);
}
});
}
})
.val(' Valider les absences ')
.appendTo($('#EditDialog'));
//*******************
// Button ' Retour '
//*******************
$('<input />')
.attr({
type:'button',
id:'newAbs'
})
.css({
float:'left',
marginTop:'5px'
})
.click(function(){
showPers();
})
.val(' Retour ')
.appendTo($('#EditDialog'));
//********************
// Button ' Nouveau '
//********************
$('<input />')
.attr({
type:'button',
disabled:false
})
.css({
float:'left',
marginTop:'5px',
marginLeft:'7px'
})
.click(function(){
if($(this).val()==' Nouveau '){
var myRow = {abs:"0", debut:'00/00/'+y, fin:'00/00/'+y, id:'0'};
myCong.jqGrid('addRowData','',myRow, 'last');
$(this).val(' Sauver ').attr('disabled',true);
}else{
}
})
.val(' Nouveau ')
.appendTo($('#EditDialog'));
}
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和结果为图像:

我担心这些问题让你烦恼,我在维基上看了一眼没有成功找到任何方法来使这些观点正确.我想找一些更详细的教程来展示一些案例.
非常感谢你,如果你能再花一些时间给我一个方法来提高jqGrid.JiheL的效率
更新2013-04-01
我已经应用了Oleg的建议,现在可以使用了.但问题仍然存在.这是图像:

对于第一行,选择框即可.第一个输入字段接收datepicker,但第二个(名为'fin'的列)不是!所有其他行都接收好日期选择器,但不是第一行的最后一个字段.这是代码:
loadComplete: function (data) {
var $self = $(this),
idPrefix = $self.jqGrid("getGridParam", "idPrefix"),
l = data.length,
i,
item,
cm;
for (i = 0; i < l; i++) {
item = data[i];
cm = $self.jqGrid("getColProp", "debut");
cm.editoptions = {
dataInit: function(element) {
//alert('deb'+i);
$(element).datepicker({
setDate:item[1],
minDate:'01/01/'+y,
maxDate:'31/12/'+y,
onSelect: function( selectedDate,inst ) {
$(element).val(selectedDate );
$(element).parent().parent().attr('changed',true);
}
})
}
};
$self.jqGrid("editRow", idPrefix + item[3]);
//
cm = $self.jqGrid("getColProp", "fin");
cm.editoptions = {
dataInit: function(element) {
//alert('fin'+i);
$(element).datepicker({
setDate:item[2],
minDate:'01/01/'+y,
maxDate:'31/12/'+y,
onSelect: function( selectedDate,inst ) {
$(element).val(selectedDate );
$(element).parent().parent().attr('changed',true);
}
})
}
};
$self.jqGrid("editRow", idPrefix + item[3]);
}
myCong.find('select').each(function(){
$(this).css({
backgroundColor:'transparent',
color:'white',
border:0,
width:155
});
});
},
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还有一次,我希望你能帮助我解决这个麻烦并关闭这个请求.非常感谢你花在帮助新手上的所有时间.JiheL
我认为很多来自你代码中的问题很常见.所以我试着回答你更详细的问题.
首先,您发布了错误的JSON数据.这条线
{"cell"[4,"Service,"Administratif","select","0:Administratif;1:Commercial;2:Magasin;3:M\u00e9canique;4:Rejointage;5:Soudure;6:Tests"]},
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包含两个错误:
"后"Service更改后,行将是如此
{"cell":[4,"Service","Administratif","select","0:Administratif;1:Commercial;2:Magasin;3:M\u00e9canique;4:Rejointage;5:Soudure;6:Tests"]},
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和JSON数据可以读取.下一个问题是在一个数组中使用数字和字符串.因为jqGrid代码行中的bug
idr = ccur !== undefined ? ccur[idn] || idr : idr;
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ids不能是整数值0.我发布了有关错误的错误报告.要使用现有的jqGrid 代码解决问题,您应该使用字符串而不是数字.例如线
{"cell":[0,"Nom ","LEBRUN","text",""]},
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应改为
{"cell":["0","Nom ","LEBRUN","text",""]},
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如果没有更改,您将拥有id重复项.第一行({"cell":[0,"Nom ","LEBRUN","text",""]}和{"cell":[1,"Pr\u00e9nom ","Jacques","text",""]},)将获得相同的id等于1而不是0和1. 这是您描述的问题的主要原因.
此外,我会建议你以下:
cellEdit:true选项.您editRow稍后在代码中使用.这意味着,您使用内联编辑,而不是单元格编辑,这意味着cellEdit:true.您无法在一个网格中组合两种编辑模式.height:250选项height:"auto"index从中删除所有属性colModel.删除colModel默认值(edittype:'text',editable:false)的所有属性mtype:'GET',scroll:false)删除jqGrid的选项cellattr回调参数,则可以替换cellattr: function (rowId, val, rawObject, cm, rdata) {...}为cellattr: function () {...}loadComplete有一个参数data,可以为您提供从服务器返回的所有数据.所以你不需要使用getDataIDs和getRowData.该阵列data.rows可以直接使用.data参数,则loadComplete可以从网格中删除不需要的列'type'和'data'列.id之后的信息,'Label','Information'那么您也可以使用id属性jsonReader并id从网格中删除隐藏列.例如,如果您id作为cell数组中的最后一个移动,则可以使用jsonReader: {id: 4}并id从网格中删除隐藏列.如果添加其他cell: ""属性,则jsonReader可以"cell":从输入数据中删除.如果要使用root已jsonReader定义为函数的属性(请参阅文档),则可以从服务器响应中删除一些不需要的数据.例如,服务器可以生成简化数据
[
["Nom ","LEBRUN","text","","0"],
["Pr\u00e9nom ","Jacques","text","","1"],
["Initiales ","LJ","text","","2"],
["Fonction ","","text","","3"],
["Service","Administratif","select","0:Administratif;1:Commercial;2:Magasin;3:M\u00e9canique;4:Rejointage;5:Soudure;6:Tests","4"],
["T\u00e9l\u00e9phone ","","text","","5"],
["Email ","","text","","6"],
["Statut ","CDI","select","0:CDI;1:CDD;2:App;3:Stg;4:Int","7"],
["Entr\u00e9 le ","2008-10-06","text","","8"],
["Sorti le ","0000-00-00","text","","9"]
]
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相应的jqGrid可以是
$("#dlgpers").jqGrid({
url: "pers.php?id=" + dataRow.id,
datatype: "json",
height: "auto",
cmTemplate: {sortable: false},
gridview: true,
colNames: ["Label", "Information"],
colModel: [
{name: "label", align: "right", width: 100,
cellattr: function () {
return ' style="font-weight:bold;margin-right:5px;border-left:0;border-top:0;" class="ui-state-active"';
}},
{name: "info", width: 200, editable: true}
],
jsonReader: {id: 4, cell: "", root: function (obj) { return obj; } },
loadComplete: function (data) {
var $self = $(this),
cm = $self.jqGrid("getColProp", "info"),
idPrefix = $self.jqGrid("getGridParam", "idPrefix"),
l = data.length,
i,
item;
for (i = 0; i < l; i++) {
item = data[i];
cm.edittype = item[2] === "select" ? "select" : "text";
cm.editoptions = { value: item[3] };
$self.jqGrid("editRow", idPrefix + item[4]);
}
},
idPrefix: "dlg",
rowNum: 10000 // to have no paging
});
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看演示:

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