如何检查Android上的互联网访问？InetAddress永远不会超时

Question

我有一个AsyncTask应该检查网络访问主机名.但是doInBackground()永远不会超时.有人有线索吗？

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

Answer 1

如果设备处于飞行模式(或者可能是在没有可用网络的其他情况下),cm.getActiveNetworkInfo()则null需要添加null支票.

修改过(Eddie的解决方案)如下:

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    return netInfo != null && netInfo.isConnectedOrConnecting();
}

还要将以下权限添加到AndroidManifest.xml:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

另一个小问题,如果你在给定的时间点绝对需要网络连接,那么最好使用netInfo.isConnected()而不是netInfo.isConnectedOrConnecting.我想这取决于个人用例.

Answer 2

网络连接/互联网访问

• isConnectedOrConnecting()(在大多数答案中使用)检查任何网络连接
• 要了解这些网络是否具有Internet访问权限,请使用以下方法之一

A)Ping服务器(简单)

// ICMP 
public boolean isOnline() {
    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int     exitValue = ipProcess.waitFor();
        return (exitValue == 0);
    }
    catch (IOException e)          { e.printStackTrace(); }
    catch (InterruptedException e) { e.printStackTrace(); }

    return false;
}

+ 可以在主线程上运行

- 在某些旧设备(Galays S3等)上不起作用,如果没有可用的互联网,它会阻塞一段时间.

B)连接到Internet上的套接字(高级)

// TCP/HTTP/DNS (depending on the port, 53=DNS, 80=HTTP, etc.)
public boolean isOnline() {
    try {
        int timeoutMs = 1500;
        Socket sock = new Socket();
        SocketAddress sockaddr = new InetSocketAddress("8.8.8.8", 53);

        sock.connect(sockaddr, timeoutMs);
        sock.close();

        return true;
    } catch (IOException e) { return false; }
}

+非常快(无论哪种方式),适用于所有设备,非常可靠

- 无法在UI线程上运行

这在每台设备上都非常可靠,而且速度非常快.它需要在单独的任务中运行(例如ScheduledExecutorService或AsyncTask).

可能的问题

• 真的够快吗？

  是的,非常快;-)

• 没有可靠的方法来检查互联网,除了在互联网上测试一些东西？

  不是我所知,但请告诉我,我会编辑我的答案.

• 如果DNS关闭怎么办？

  Google DNS(例如8.8.8.8)是世界上最大的公共DNS.截至2013年,它每天为1300亿个请求提供服务.我们只是说,你的应用可能不是当天的话题.

• 需要哪些权限？

  <uses-permission android:name="android.permission.INTERNET" />
  

  只是互联网访问 - 惊喜^^(顺便说一句,你有没有想过,如果没有这个许可,这里建议的一些方法甚至可能有一个关于互联网访问的远程胶水？)

 

额外:一次性AsyncTask示例

class InternetCheck extends AsyncTask<Void,Void,Boolean> {

    private Consumer mConsumer;
    public  interface Consumer { void accept(Boolean internet); }

    public  InternetCheck(Consumer consumer) { mConsumer = consumer; execute(); }

    @Override protected Boolean doInBackground(Void... voids) { try {
        Socket sock = new Socket();
        sock.connect(new InetSocketAddress("8.8.8.8", 53), 1500);
        sock.close();
        return true;
    } catch (IOException e) { return false; } }

    @Override protected void onPostExecute(Boolean internet) { mConsumer.accept(internet); }
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    new InternetCheck(internet -> { /* do something with boolean response */ });

额外:一次性RxJava/RxAndroid示例(Kotlin)

fun hasInternetConnection(): Single<Boolean> {
  return Single.fromCallable {
    try {
      // Connect to Google DNS to check for connection
      val timeoutMs = 1500
      val socket = Socket()
      val socketAddress = InetSocketAddress("8.8.8.8", 53)

      socket.connect(socketAddress, timeoutMs)
      socket.close()

      true
    } catch (e: IOException) {
      false
    }
  }
  .subscribeOn(Schedulers.io())
  .observeOn(AndroidSchedulers.mainThread())
}

///////////////////////////////////////////////////////////////////////////////////
    // Usage

    hasInternetConnection().subscribe { hasInternet -> /* do something */}

Answer 3

不需要复杂.最简单的框架方式是使用ACCESS_NETWORK_STATE权限并只创建一个连接的方法

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    return cm.getActiveNetworkInfo() != null && 
       cm.getActiveNetworkInfo().isConnectedOrConnecting();
}

requestRouteToHost如果您有特定的主机和连接类型(wifi /移动),您也可以使用.

您还需要:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

在你的Android清单中.

Answer 4

要开始getActiveNetworkInfo()工作,您需要将以下内容添加到清单中.

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

Answer 5

看一下ConnectivityManager类.您可以使用此类来获取有关主机上活动连接的信息.http://developer.android.com/reference/android/net/ConnectivityManager.html

编辑:你可以使用

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_MOBILE) 

要么

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_WIFI) 

并解析返回的NetworkInfo对象的DetailedState枚举

编辑编辑:要了解您是否可以访问主机,您可以使用

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .requestRouteToHost(TYPE_WIFI, int hostAddress)

显然,我使用Context.getSystemService(Context.CONNECTIVITY_SERVICE)作为代理来说

ConnectivityManager cm = Context.getSystemService(Context.CONNECTIVITY_SERVICE);
cm.yourMethodCallHere();

Answer 6

检查这段代码......它对我有用:)

public static void isNetworkAvailable(final Handler handler, final int timeout) {
    // ask fo message '0' (not connected) or '1' (connected) on 'handler'
    // the answer must be send before before within the 'timeout' (in milliseconds)

    new Thread() {
        private boolean responded = false;   
        @Override
        public void run() { 
            // set 'responded' to TRUE if is able to connect with google mobile (responds fast) 
            new Thread() {      
                @Override
                public void run() {
                    HttpGet requestForTest = new HttpGet("http://m.google.com");
                    try {
                        new DefaultHttpClient().execute(requestForTest); // can last...
                        responded = true;
                    } 
                    catch (Exception e) {
                    }
                } 
            }.start();

            try {
                int waited = 0;
                while(!responded && (waited < timeout)) {
                    sleep(100);
                    if(!responded ) { 
                        waited += 100;
                    }
                }
            } 
            catch(InterruptedException e) {} // do nothing 
            finally { 
                if (!responded) { handler.sendEmptyMessage(0); } 
                else { handler.sendEmptyMessage(1); }
            }
        }
    }.start();
}

然后,我定义处理程序:

Handler h = new Handler() {
    @Override
    public void handleMessage(Message msg) {

        if (msg.what != 1) { // code if not connected

        } else { // code if connected

        }   
    }
};

...并启动测试:

isNetworkAvailable(h,2000); // get the answser within 2000 ms

Answer 7

在此链接中找到并修改(!):

在您的清单文件中至少添加:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

如果您正在访问它,您可能已经拥有INTERNET权限.然后,允许测试连接的布尔函数是:

private boolean checkInternetConnection() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    // test for connection
    if (cm.getActiveNetworkInfo() != null
            && cm.getActiveNetworkInfo().isAvailable()
            && cm.getActiveNetworkInfo().isConnected()) {
        return true;
    } else {
        Log.v(TAG, "Internet Connection Not Present");
        return false;
    }
}

Answer 8

我做了这个代码,它是最简单的,它只是一个布尔值.通过询问if(isOnline()){

如果有连接并且它可以连接到页面状态代码200(稳定连接),则会获得.

确保添加正确INTERNET和ACCESS_NETWORK_STATE权限.

public boolean isOnline() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    if (netInfo != null && netInfo.isConnected()) {
        try {
            URL url = new URL("http://www.google.com");
            HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
            urlc.setConnectTimeout(3000);
            urlc.connect();
            if (urlc.getResponseCode() == 200) {
                return new Boolean(true);
            }
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
    return false;
}

Answer 9

它对我有用:

要验证网络可用性:

private Boolean isNetworkAvailable() {
ConnectivityManager connectivityManager 
      = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
return activeNetworkInfo != null && activeNetworkInfo.isConnectedOrConnecting();}

验证互联网访问:

public Boolean isOnline() {
    try {
        Process p1 = java.lang.Runtime.getRuntime().exec("ping -c 1 www.google.com");
        int returnVal = p1.waitFor();
        boolean reachable = (returnVal==0);
        return reachable;
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return false;
}

Answer 10

这不止一种方式

首先,最短但效率低的方式

仅需要网络状态权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

那么这个方法,

 public boolean activeNetwork () {
        ConnectivityManager cm =
                (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);

        NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
        boolean isConnected = activeNetwork != null &&
                activeNetwork.isConnected();

        return isConnected;

    }

如答案所示ConnectivityManager是一个解决方案,我只是在一个方法中添加它这是一个简化的方法
ConnectivityManager如果网络访问不是因特网访问,所有使用返回true,意味着你的WiFi连接到路由器但路由器没有互联网它返回true,它检查连接可用性

第二,有效的方式

需要网络状态和Internet权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />

然后这节课,

 public class CheckInternetAsyncTask extends AsyncTask<Void, Integer, Boolean> {

        private Context context;

        public CheckInternetAsyncTask(Context context) {
            this.context = context;
        }

        @Override
        protected Boolean doInBackground(Void... params) {

            ConnectivityManager cm =
                    (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);

            assert cm != null;
            NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
            boolean isConnected = activeNetwork != null &&
                    activeNetwork.isConnected();


            if (isConnected) {
                try {
                    HttpURLConnection urlc = (HttpURLConnection)
                            (new URL("http://clients3.google.com/generate_204")
                                    .openConnection());
                    urlc.setRequestProperty("User-Agent", "Android");
                    urlc.setRequestProperty("Connection", "close");
                    urlc.setConnectTimeout(1500);
                    urlc.connect();
                    if (urlc.getResponseCode() == 204 &&
                            urlc.getContentLength() == 0)
                        return true;

                } catch (IOException e) {
                    Log.e("TAG", "Error checking internet connection", e);
                    return false;
                }
            } else {
                Log.d("TAG", "No network available!");
                return false;
            }


            return null;
        }

        @Override
        protected void onPostExecute(Boolean result) {
            super.onPostExecute(result);
            Log.d("TAG", "result" + result);

            if(result){
                // do ur code
            }

        }


    }

呼叫 CheckInternetAsyncTask

new CheckInternetAsyncTask(getApplicationContext()).execute();

一些解释: -

• 你必须检查互联网AsyncTask,否则它可以抛出android.os.NetworkOnMainThreadException一些情况

• ConnectivityManager 如果为true,则用于检查网络访问请求(Ping)

• 请求发送到http://clients3.google.com/generate_204,已知这个众所周知的URL返回一个HTTP状态204的空页面,这比http://www.google.com读取它更快,更有效.如果你有网站,只有你在应用程序中使用它,首选你的网站而不是谷歌

• 超时可以改变范围(20ms - > 2000ms),常用1500ms

Answer 11

到目前为止,我所看到的最短和最干净的方式应该是:

public final static boolean isConnected( Context context )
{   
   final ConnectivityManager connectivityManager = 
         (ConnectivityManager) context.getSystemService( Context.CONNECTIVITY_SERVICE );  
   final NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();    
   return networkInfo != null && networkInfo.isConnected();
}

PS:这不会ping任何主机,它只是检查connectionstatus,所以如果您的路由器没有互联网连接并且您的设备已连接到它,这种方法将返回true,尽管您没有互联网.
对于实际测试,我建议执行HttpHead请求(例如,到www.google.com)并检查状态,如果它的200 OK一切正常并且您的设备有互联网连接.

Answer 12

这是我使用的方法:

public boolean isNetworkAvailable(final Context context) {
    return ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE)).getActiveNetworkInfo() != null;
}

更好的是,检查以确保它"连接":

public boolean isNetworkAvailable(final Context context) {
    final ConnectivityManager connectivityManager = ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE));
    return connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected();
}

以下是如何使用该方法:

if (isNetworkAvailable(context)) {
    // code here
} else {
    // code
}

需要许可:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

/sf/answers/1128744081/

Answer 13

移动设备上的一个重要用例是确保存在实际连接.当移动用户进入具有"强制门户"的Wifi网络时,这是一个常见问题,他们需要登录.我在后台使用此阻止功能以确保存在连接.

/*
 * Not Thread safe. Blocking thread. Returns true if it
 * can connect to URL, false and exception is logged.
 */
public boolean checkConnectionHttps(String url){
    boolean responded = false;
    HttpGet requestTest = new HttpGet(url);
    HttpParams params = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(params, 3000);
    HttpConnectionParams.setSoTimeout(params, 5000);
    DefaultHttpClient client = new DefaultHttpClient(params);
    try {
        client.execute(requestTest);
        responded = true;
    } catch (ClientProtocolException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
    } catch (IOException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
        e.printStackTrace();
    }
    return responded;
}

Answer 14

Kotlin 和协程

我已将该函数放在 a 中ViewModel，该函数具有viewModelScope. 使用 observableLiveData通知活动有关连接的信息。

视图模型

 fun checkInternetConnection(timeoutMs: Int) {
        viewModelScope.launch(Dispatchers.IO) {
            try {
                val socket = Socket()
                val socketAddress = InetSocketAddress("8.8.8.8", 53)

                socket.connect(socketAddress, timeoutMs)
                socket.close()

                _connection.postValue(true)
            }
            catch(ex: IOException) {
                _connection.postValue(false)
            }
        }
    }

 private val _connection = MutableLiveData<Boolean>()
 val connection: LiveData<Boolean> = _connection

活动

 private fun checkInternetConnection() {
     viewModel.connection.observe(this) { hasInternet ->
         if(!hasInternet) {
             //hasn't connection
         }
         else {
            //has connection
         }
     }
  }

Answer 15

您可以遍历所有网络连接并判断是否至少有一个可用连接:

public boolean isConnected() {
    boolean connected = false;

    ConnectivityManager cm = 
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    if (cm != null) {
        NetworkInfo[] netInfo = cm.getAllNetworkInfo();

        for (NetworkInfo ni : netInfo) {
            if ((ni.getTypeName().equalsIgnoreCase("WIFI")
                    || ni.getTypeName().equalsIgnoreCase("MOBILE"))
                    && ni.isConnected() && ni.isAvailable()) {
                connected = true;
            }

        }
    }

    return connected;
}

Answer 16

它对我有用.试试看.

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    try {
        URL url = new URL("http://stackoverflow.com/posts/11642475/edit" );
        //URL url = new URL("http://www.nofoundwebsite.com/" );
        executeReq(url);
        Toast.makeText(getApplicationContext(), "Webpage is available!", Toast.LENGTH_SHORT).show();
    }
    catch(Exception e) {
        Toast.makeText(getApplicationContext(), "oops! webpage is not available!", Toast.LENGTH_SHORT).show();
    }
}

private void executeReq(URL urlObject) throws IOException
{
    HttpURLConnection conn = null;
    conn = (HttpURLConnection) urlObject.openConnection();
    conn.setReadTimeout(30000);//milliseconds
    conn.setConnectTimeout(3500);//milliseconds
    conn.setRequestMethod("GET");
    conn.setDoInput(true);

    // Start connect
    conn.connect();
    InputStream response =conn.getInputStream();
    Log.d("Response:", response.toString());
}}

Answer 17

对我来说,检查Activity类中的连接状态不是一个好习惯,因为

ConnectivityManager cm =
    (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

应该在那里调用,或者你需要将你的Activity实例(上下文)下推到连接处理程序类,以便能够检查那里的连接状态当没有可用的连接(wifi,网络)时,我捕获了UnknownHostException异常:

JSONObject jObj = null;
Boolean responded = false;
HttpGet requestForTest = new HttpGet("http://myserver.com");
try {
    new DefaultHttpClient().execute(requestForTest);
    responded = true;
} catch (UnknownHostException e) {
    jObj = new JSONObject();
    try {
        jObj.put("answer_code", 1);
        jObj.put("answer_text", "No available connection");
    } catch (Exception e1) {}
    return jObj;
} catch (IOException e) {
    e.printStackTrace();
}

通过这种方式,我可以处理这种情况以及同一类中的其他情况(我的服务器总是以json字符串回复)

Answer 18

该方法为您提供了一种非常快速的方法（用于实时反馈）或一种较慢的方法（用于需要可靠性的一次性检查）的选项。

public boolean isNetworkAvailable(bool SlowButMoreReliable) {
    bool Result = false; 
    try {
        if(SlowButMoreReliable){
            ConnectivityManager MyConnectivityManager = null;
            MyConnectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

            NetworkInfo MyNetworkInfo = null;
            MyNetworkInfo = MyConnectivityManager.getActiveNetworkInfo();

            Result = MyNetworkInfo != null && MyNetworkInfo.isConnected();

        } else
        {
            Runtime runtime = Runtime.getRuntime();
            Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");

            int i = ipProcess.waitFor();

            Result = i== 0;

        }

    } catch(Exception ex)
    {
        //Common.Exception(ex); //This method is one you should have that displays exceptions in your log
    }
    return Result;
}

Answer 19

我使用此代码而不是InetAddress:

    try {

        URL url = new URL("http://"+params[0]);

        HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
        urlc.setRequestProperty("User-Agent", "Android Application:"+Z.APP_VERSION);
        urlc.setRequestProperty("Connection", "close");
        urlc.setConnectTimeout(1000 * 30); // mTimeout is in seconds
        urlc.connect();
        if (urlc.getResponseCode() == 200) {
            Main.Log("getResponseCode == 200");
            return new Boolean(true);
        }
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

Answer 20

检查Android网络/互联网连接状态并不复杂.以下DetectConnection课程将帮助您检查此状态:

import android.content.Context;
import android.net.ConnectivityManager;

public class DetectConnection {
    public static boolean checkInternetConnection(Context context) {
        ConnectivityManager con_manager = (ConnectivityManager) context
                                .getSystemService(Context.CONNECTIVITY_SERVICE);

        if (con_manager.getActiveNetworkInfo() != null
            && con_manager.getActiveNetworkInfo().isAvailable()
            && con_manager.getActiveNetworkInfo().isConnected()) {
                return true;
        } else {
            return false;
        }
    }
}

有关更多详细信息,请访问 如何检查Android网络/ Internet连接状态

Answer 21

最佳方法:

public static boolean isOnline() {
    try {
    InetAddress.getByName("google.com").isReachable(3);

    return true;
    } catch (UnknownHostException e){
    return false;
    } catch (IOException e){
    return false;
    }
    }

Answer 22

以下是我Utils班上的代码:

public static boolean isNetworkAvailable(Context context) {
        ConnectivityManager connectivityManager 
              = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
        return activeNetworkInfo != null && activeNetworkInfo.isConnected();
}

Answer 23

public class Network {

Context context;

public Network(Context context){
    this.context = context;
}

public boolean isOnline() {
    ConnectivityManager cm =
            (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);

    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    return activeNetwork != null &&
                          activeNetwork.isConnectedOrConnecting();
}

}

Answer 24

您可以使用此方法检测网络可用性 -

public static boolean isDeviceOnline(Context context) {
        boolean isConnectionAvail = false;
        try {
            ConnectivityManager cm = (ConnectivityManager) context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);
            NetworkInfo netInfo = cm.getActiveNetworkInfo();
            return netInfo.isConnected();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return isConnectionAvail;
    }

Answer 25

这在 android 文档 http://developer.android.com/training/monitoring-device-state/connectivity-monitoring.html 中有介绍

Answer 26

检查我们是否与isAvailable()连接以及是否可以与isConnected()建立连接非常重要

private static ConnectivityManager manager;

public static boolean isOnline(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.isAvailable() && networkInfo.isConnected();
}

您可以确定网络活动WiFi的类型：

public static boolean isConnectedWifi(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_WIFI;
}

或移动Móvil：

public static boolean isConnectedMobile(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_MOBILE;
}

不要忘记权限：

    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
   <uses-permission android:name="android.permission.INTERNET" />

Answer 27

我已经应用了@Levit提供的解决方案并创建了不会调用额外Http请求的函数.

它将解决错误 Unable to Resolve Host

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在称之为,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}