use*_*779 1 sqlite android cursor where
我需要从dan == table_column_one和vrijeme == table_column_two的数据库中返回ID值.我不知道该怎么做.
public static int returnID(String dan, int vrijeme){
Cursor cursor;
int IDRQ;
cursor = db.query
(
TABLE_NAME,
new String[] { TABLE_COLUMN_ID, TABLE_COLUMN_ONE, TABLE_COLUMN_TWO },
new String[] {TABLE_COLUMN_ONE + " like " + "'%" + dan + "%'", TABLE_COLUMN_TWO + " like " + "'%" + vrijeme + "%'"}, null, null, null, null
);
cursor.moveToFirst();
IDRQ = cursor.getInt(0);
return IDRQ;
} );
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这就是我尝试的方式,当然,这是错误的.
在SQLiteDatabase.query()中,选择分为两部分.where子句(a String)和whereArgs(数组String).
要添加一个以上的条件,你可以使用WHERE子句AND或OR,就像&&或||在Java中.
where子句中的问号绑定到whereArgs数组中的一个字符串.
cursor = db.query(TABLE_NAME, new String[] { TABLE_COLUMN_ID, TABLE_COLUMN_ONE, TABLE_COLUMN_TWO },
TABLE_COLUMN_ONE + " LIKE ? AND " + TABLE_COLUMN_TWO + " LIKE ?",
new String[] {"%" + dan + "%", "%" + vrijeme + "%"},
null, null, null, null);
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