从十六进制字符串转换为unicode

Question

如何将'dead'字符串转换为unicode字符串u'\xde\xad'？

这样做:

from binascii import unhexlify
out = ''.join(x for x in [unhexlify('de'), unhexlify('ad')])

创建一个<type 'str'>字符串'\xde\xad'

试图像这样使用Unicode.join():

from binascii import unhexlify
out = ''.join(x for x in [u'', unhexlify('de'), unhexlify('ad')])

导致错误:

UnicodeDecodeError: 'ascii' codec can't decode byte 0xde in position 0: ordinal not in range(128)

Answer 1

Unicode旨在与Latin-1兼容,您可以使用它并简单地解码bytestring:

In [2]: unhexlify('dead').decode('latin1')
Out[2]: u'\xde\xad'