Sha*_*mar 5 jquery jquery-validate
我试图在Jquery中使用自定义验证.所有的编码部分都是正确的,但我没有得到它出错的地方......这是代码的一部分.
Password:<input type="password" id="pnameTxt" name="pnameTxt" placeholder="Enter Password" size=12 class='required'><br>
Confirm Password:<input type="password" id="pnameTxt2" name="pnameTxt2" placeholder="Retype Password" size=15 class='required passwordCheck'><br>
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自定义验证方法:
$.validator.addMethod("passwordCheck",function (value,element){
return value==$("#pnameTxt").val();
}, 'Password and Confirm Password should be same');
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Spa*_*rky 34
你的代码正在运行.使用初始化插件时,还必须将规则分配给字段.validate().
工作演示:http: //jsfiddle.net/KrLkF/
$(document).ready(function () {
$.validator.addMethod("passwordCheck", function (value, element) {
return value == $("#pnameTxt").val();
}, 'Password and Confirm Password should be same');
$('#myform').validate({ // initialize the plugin
rules: {
pnameTxt2: {
passwordCheck: true
}
}
});
});
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但是,您不需要为此功能编写自定义方法.jQuery Validate插件已有equalTo规则,以下是如何使用它.
工作演示:http: //jsfiddle.net/tdhHt/
$(document).ready(function () {
$('#myform').validate({ // initialize the plugin
rules: {
pnameTxt2: {
equalTo: "#pnameTxt" // using `id` of the other field
}
},
messages: {
pnameTxt2: {
equalTo: "Password and Confirm Password should be same"
}
}
});
});
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您是否正确初始化了验证插件?当我将 html 放入 a 中form时,initialize the plugin它会按预期工作。
<form id="test">
Password:<input type="password" id="pnameTxt" name="pnameTxt" placeholder="Enter Password" size=12 class='required'><br>
Confirm Password:<input type="password" id="pnameTxt2" name="pnameTxt2" placeholder="Retype Password" size=15 class='required passwordCheck'><br>
<input type="submit">
</form>
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<form id="test">
Password:<input type="password" id="pnameTxt" name="pnameTxt" placeholder="Enter Password" size=12 class='required'><br>
Confirm Password:<input type="password" id="pnameTxt2" name="pnameTxt2" placeholder="Retype Password" size=15 class='required passwordCheck'><br>
<input type="submit">
</form>
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