如何在SQL Server 2008中创建序列

Question

我使用以下代码在SQL Server中创建序列.但它将错误显示为未知对象类型.请给出一个解决方案

这是我的代码:

create sequence seqval start with 100 increment by 1 minvalue 0 maxvalue 0 no cycle  
 no cache;

提前致谢

Answer 1

你可以这样做.

--Create a dummy TABLE to generate a SEQUENCE. No actual records will be stored.
CREATE TABLE SequenceTABLE
(
    ID BIGINT IDENTITY  
);
GO

--This procedure is for convenience in retrieving a sequence.
CREATE PROCEDURE dbo.GetSEQUENCE ( @value BIGINT OUTPUT)
AS
    --Act like we are INSERTing a row to increment the IDENTITY
    BEGIN TRANSACTION;
    INSERT SequenceTABLE WITH (TABLOCKX) DEFAULT VALUES;
    ROLLBACK TRANSACTION;
    --Return the latest IDENTITY value.
    SELECT @value = SCOPE_IDENTITY();
GO

--Example execution
DECLARE @value BIGINT;
EXECUTE dbo.GetSEQUENCE @value OUTPUT;
SELECT @value AS [@value];
GO

Answer 2

你确定你要参加2012年吗？我没有遇到任何问题：

CREATE SEQUENCE seqval
START WITH 100
INCREMENT BY 1 
minvalue 100 maxvalue 10000 NO CYCLE

你的 0,0 值对我来说产生了一个语法错误，但这是一个清晰而简单的错误。

The minimum value for sequence object 'seqval' must be less than its maximum value.