unj*_*nj2 5 scheme continuations racket
我很惊讶PLTScheme中的"错误"功能.如果我有一个除零,它不会做任何其他递归,只是从调用堆栈出来并给我一个错误.
在所有功能之前是否存在隐含的延续?错误是否会丢弃调用堆栈?有没有人对此有任何想法?
在PLT Scheme中,过程错误引发异常exn:fail,其中包含错误字符串.所有定义都没有"隐式捕获".请看以下示例:
;; test.ss
(define (a d)
(printf "~a~n" (/ 10 d)))
(a 0) ;; The interpreter will exit here.
(printf "OK~n")
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从命令行执行上面的脚本,你会看到在打印之后存在解释器
/: division by zero
=== context ===
/home/user/test.ss:1:0: a
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如果在用户程序中未处理异常,则会将其传播到核心解释器,默认处理程序处理该异常,即打印异常并退出.换句话说,翻译只是说,"提出了一个例外,我不知道如何处理它,所以我退出了".这与JVM或其他虚拟机处理异常的方式没有太大区别.
要了解有关PLT Scheme的异常处理机制的更多信息,请阅读MzScheme语言手册中的with-handlers和dynamic-wind.使用这些,您甚至可以模拟Java的try-catch-finally块.
(define (d a b)
(try
(printf "~a~n" (/ a b))
(catch (lambda (ex)
(printf "Error: ~a" ex)))
(finally
(if (> b -2)
(d a (sub1 b))))))
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以下是使上述成为可能的语法扩展:
;; try-catch-finally on top of with-handlers and dynamic-wind.
(define-syntax try
(syntax-rules (catch finally)
((_ try-body ... (catch catch-proc))
(with-handlers (((lambda (ex) #t)
(lambda (ex)
(catch-proc ex))))
(begin
try-body ...)))
((_ try-body ... (catch catch-proc) (finally fin-body ...))
(dynamic-wind
(lambda () ())
(lambda ()
(with-handlers (((lambda (ex) #t)
(lambda (ex)
(catch-proc ex))))
(begin
try-body ...)))
(lambda () fin-body ...)))
((_ try-body ... (finally fin-body ...))
(dynamic-wind
(lambda () ())
(lambda () try-body ...)
(lambda () fin-body ...)))))
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