嵌入luajit未定义的引用

Question

我试图将(静态)luajit嵌入到c ++应用程序中失败了.我已经按照luajit网站上的步骤无效,用Google搜索主题并没有获得相关信息,并尝试了我能想到的每件事.

好像我正在运行的问题似乎是g ++没有正确地链接它,或者也许luajit没有正确构建.

这是我正在尝试编译的内容:

#include <lua.h>
#include <lauxlib.h>
#include <lualib.h>

int main(void)
{
    lua_State *L = luaL_newstate();
    luaL_openlibs(L);
    lua_close(L);

    return 0;
}

我得到的undefined reference错误是一个错误,几乎就像我根本没有链接luajit.

main.cpp:7: undefined reference to `luaL_newstate()'
main.cpp:9: undefined reference to `luaL_openlibs(lua_State*)'
main.cpp:10: undefined reference to `lua_close(lua_State*)'

在设置链接选项后,我正在尝试用eclipse cdt(mingw)编译它,如下所示:

Library Paths:        D:/includes/LuaJIT-2.0.1/src
Includes (GNU G++):   D:/includes/LuaJIT-2.0.1/src
Libraries:            luajit

而eclipse cdt似乎正在尝试编译它如下:

g++ -ID:/includes/LuaJIT-2.0.1/src -O0 -g3 -pedantic-errors -Wall -Wextra -Werror -Wconversion -c -fmessage-length=0 -Weffc++ -std=c++11 -o "source\\main.o" "..\\source\\main.cpp" 
g++ -LD:/includes/LuaJIT-2.0.1/src -o test.exe "source\\main.o" -lluajit

我从他们的下载页面下载了LuaJIT-2.0.1 zip(最新版本),并按照以下安装指南进行操作:

• 解开它.
• 解雇了一个cmd并且接着 LuaJIT-2.0.1/src/
• 跑了make BUILDMODE=static,得到了一个很好的OK Successfully built LuaJIT消息

除此之外,没有很多关于嵌入luajit的信息,甚至在安装指南中都没有.

但是,在src文件夹中点击以luaL_newstate返回匹配项libluajit.a.

grep -r "luaL_newstate" .

./host/genminilua.lua:  lua_State *L = luaL_newstate();
./host/minilua.c:static lua_State*luaL_newstate(void){
./host/minilua.c:lua_State*L=luaL_newstate();
./lauxlib.h:LUALIB_API lua_State *(luaL_newstate) (void);
Binary file ./libluajit.a matches
./lib_aux.c:LUALIB_API lua_State *luaL_newstate(void)
./lib_aux.c:LUALIB_API lua_State *luaL_newstate(void)
./lib_aux.c:  fputs("Must use luaL_newstate() for 64 bit target\n", stderr);
Binary file ./lib_aux.o matches
./lua.h:#define lua_open()      luaL_newstate()
Binary file ./luajit.exe matches
Binary file ./luajit.o matches

我正在使用:

• MinGW的的 g++ (rev, Built by MinGW-builds project) 4.8.0 20130314 (experimental)
• MinGW的的 GNU Make 3.82.90 Built for i686-pc-msys
• Win8 64bit

Answer 1

将你的include指令包装进去extern "C" { ... }