Rob*_*ori 7 requirejs backbone.js marionette
我正试图在Marionette CollectionView中动态操作itemViews.集合具有相同的模型,但我在模型中定义了templateName参数.
问题是,我可以通过这个参数操纵ItemView模板吗?
ItemView控件:
define(['text!templates/ComponentItemViewTemplate.html','models/ComponentModel'], function (template, model) {
var ItemView = Backbone.Marionette.ItemView.extend({
template: _.template(template),
model: model
});
return ItemView;
});
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的CollectionView:
define(['views/ComponentItemView', 'views/LoadingView'], function(ItemView, LoadingView) {
var ComponentListView = Backbone.Marionette.CollectionView.extend({
emptyView : LoadingView,
id: "component-list",
itemView: ItemView,
events: {
'click .title span' : 'show'
},
appendHtml: function(collectionView, itemView, index){//i would like to render different templates, for different models.
itemView.$el.draggable({ helper: "clone", cancel: ".component .title span", connectToSortable: ".ui-sortable" });
collectionView.$el.append(itemView.el);
},
show: function(r) {
var target = $(r.target);
if( target.parent().hasClass('open') ){
target.parent().removeClass('open');
target.parent().next().slideDown('fast');
}else{
target.parent().addClass('open');
target.parent().next().slideUp('fast');
}
}
});
return ComponentListView;
});
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谢谢!
kir*_*uga 25
您可以覆盖getTemplate函数并在那里编写自定义逻辑.该木偶文档建议以下选项:
MyView = Backbone.Marionette.ItemView.extend({
getTemplate: function(){
if (this.model.get("foo")){
return "#some-template";
} else {
return "#a-different-template";
}
}
});
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我认为gumballhead走在正确的轨道上.您可以覆盖该getTemplate功能来执行此操作.
MyCollectionView = Marionette.CollectionView.extend({
// ...
getItemView: function(item){
// get the template from the item... or wherever else it comes from
return new MyViewType({
template: item.get("the-template")
});
}
});
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希望能满足您的需求
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