Mat*_*att 22 sql postgresql join left-join
我想从表中删除取决于另一个引用第一个表的表上存在的数据,但是,我有代码可以工作并显示当我将其作为SELECT stetement运行时要删除的值,但是当我将其更改为删除它给了我错误,我不明白为什么他们在那里.
DELETE leadCustomer.* FROM coursework.leadCustomer LEFT JOIN coursework.flightBooking
ON leadCustomer.customerID = flightBooking.customerID
WHERE leadCustomer.customerID NOT IN (
SELECT customerID FROM (SELECT customerID, status FROM coursework.flightBooking) AS
StatusCount where status IN ('R','H') GROUP BY customerID
)
AND leadCustomer.customerID = 8;
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错误:
ERROR: syntax error at or near "leadCustomer"
LINE 1: DELETE leadCustomer.* FROM coursework.leadCustomer LEFT JOIN...
^
********** Error **********
ERROR: syntax error at or near "leadCustomer"
SQL state: 42601
Character: 8
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我正在使用postgres
小智 53
样品.表'A'中的删除记录表'H'中没有记录
DELETE A FROM ARTICULO_ALMACEN A
LEFT JOIN HISTORICO_UNION H
ON A.COD_ARTICULO = H.COD_ARTICULO
AND A.COD_ALMACEN = H.COD_ARTICULO_ALMACEN
AND A.TPROPIEDAD1 = H.PROPIEDAD1
AND A.TPROPIEDAD2 = H.PROPIEDAD2
AND A.TPROPIEDAD3 = H.PROPIEDAD3
WHERE H.COD_ARTICULO IS NULL
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Lau*_* S. 16
从我看到的地方,你实际上并不需要联接来执行此操作......
DELETE FROM coursework.leadCustomer
WHERE leadCustomer.customerID NOT IN (
SELECT distinct customerID FROM coursework.flightBooking where status IN ('R','H')
)
AND leadCustomer.customerID = 8;
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它将使用以下客户ID删除leadcustomer中的所有记录:1)与8不同2)不在表格"R"或"H"的表格中
这不是你想要做的吗?
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