Python中用户友好的时间格式？

Question

Python:我需要在"1天前","两小时前"格式中显示文件修改时间.

有什么准备好的吗？它应该是英文的.

Answer 1

该代码最初发布在博客文章"Python Pretty Date function"(http://evaisse.com/post/93417709/python-pretty-date-function)上

此处转载此博客帐户已被暂停且页面不再可用.

def pretty_date(time=False):
    """
    Get a datetime object or a int() Epoch timestamp and return a
    pretty string like 'an hour ago', 'Yesterday', '3 months ago',
    'just now', etc
    """
    from datetime import datetime
    now = datetime.now()
    if type(time) is int:
        diff = now - datetime.fromtimestamp(time)
    elif isinstance(time,datetime):
        diff = now - time
    elif not time:
        diff = now - now
    second_diff = diff.seconds
    day_diff = diff.days

    if day_diff < 0:
        return ''

    if day_diff == 0:
        if second_diff < 10:
            return "just now"
        if second_diff < 60:
            return str(second_diff) + " seconds ago"
        if second_diff < 120:
            return "a minute ago"
        if second_diff < 3600:
            return str(second_diff / 60) + " minutes ago"
        if second_diff < 7200:
            return "an hour ago"
        if second_diff < 86400:
            return str(second_diff / 3600) + " hours ago"
    if day_diff == 1:
        return "Yesterday"
    if day_diff < 7:
        return str(day_diff) + " days ago"
    if day_diff < 31:
        return str(day_diff / 7) + " weeks ago"
    if day_diff < 365:
        return str(day_diff / 30) + " months ago"
    return str(day_diff / 365) + " years ago"

Answer 2

如果你碰巧使用Django,那么版本1.4中的新功能就是naturaltime模板过滤器.

要使用它,请先在settings.py中添加'django.contrib.humanize'到您INSTALLED_APPS的设置,然后添加到您{% load humanize %}正在使用过滤器的模板中.

然后,在你的模板中,如果你有一个日期时间变量my_date,你可以通过使用来打印它与现在的距离{{ my_date|naturaltime }},它将被渲染为类似的东西4 minutes ago.

Django 1.4中的其他新东西.

集合naturaltime中的文档和其他过滤器django.contrib.humanize.

Answer 3

在寻找处理未来日期的额外要求时,我找到了这个:http: //pypi.python.org/pypi/py-pretty/1

示例代码(来自网站):

from datetime import datetime, timedelta
now = datetime.now()
hrago = now - timedelta(hours=1)
yesterday = now - timedelta(days=1)
tomorrow = now + timedelta(days=1)
dayafter = now + timedelta(days=2)

import pretty
print pretty.date(now)                      # 'now'
print pretty.date(hrago)                    # 'an hour ago'
print pretty.date(hrago, short=True)        # '1h ago'
print pretty.date(hrago, asdays=True)       # 'today'
print pretty.date(yesterday, short=True)    # 'yest'
print pretty.date(tomorrow)                 # 'tomorrow'

Answer 4

有humanize包：

>>> from datetime import datetime, timedelta
>>> import humanize # $ pip install humanize
>>> humanize.naturaltime(datetime.now() - timedelta(days=1))
'a day ago'
>>> humanize.naturaltime(datetime.now() - timedelta(hours=2))
'2 hours ago'

它支持本地化l10n，国际化 i18n：

>>> _ = humanize.i18n.activate('ru_RU')
>>> print humanize.naturaltime(datetime.now() - timedelta(days=1))
???? ?????
>>> print humanize.naturaltime(datetime.now() - timedelta(hours=2))
2 ???? ?????

Answer 5

您也可以使用箭头包来做到这一点

来自github页面:

>>> import arrow
>>> utc = arrow.utcnow()
>>> utc = utc.replace(hours=-1)
>>> local.humanize()
'an hour ago'

Answer 6

Jed Smith与之相关的答案是好的,我使用了一年左右,但我认为可以通过以下几种方式改进:

• 很高兴能够根据前面的单位定义每个时间单位,而不是在整个代码中散布像3600,86400等"魔术"常量.
• 经过多次使用后,我发现我不想那么急切地去下一个单位.例如:7天和13天都显示为"1周"; 我宁愿看"7天"或"13天".

这是我想出的:

def PrettyRelativeTime(time_diff_secs):
    # Each tuple in the sequence gives the name of a unit, and the number of
    # previous units which go into it.
    weeks_per_month = 365.242 / 12 / 7
    intervals = [('minute', 60), ('hour', 60), ('day', 24), ('week', 7),
                 ('month', weeks_per_month), ('year', 12)]

    unit, number = 'second', abs(time_diff_secs)
    for new_unit, ratio in intervals:
        new_number = float(number) / ratio
        # If the new number is too small, don't go to the next unit.
        if new_number < 2:
            break
        unit, number = new_unit, new_number
    shown_num = int(number)
    return '{} {}'.format(shown_num, unit + ('' if shown_num == 1 else 's'))

注意每个元组intervals是如何易于解释和检查的:a 'minute'是60秒; 一个'hour'是60分钟; 唯一的软糖是设定weeks_per_month其平均值; 鉴于申请,这应该没问题.(请注意,一目了然,最后三个常数乘以365.242,即每年的天数.)

我的功能的一个缺点是它不会在"## units"模式之外做任何事情:"昨天","刚才",等等.然后,原始的海报并没有要求这些花哨的术语,所以我更喜欢我的功能,因为它的简洁性和数字常数的可读性.:)