O.r*_*rka 116 python random select file list
到目前为止,我已经想出了如何导入文件,创建新文件以及随机化列表.
我无法从列表中随机选择50个项目来写入文件?
def randomizer(input,output1='random_1.txt',output2='random_2.txt',output3='random_3.txt',output4='random_total.txt'):
#Input file
query=open(input,'r').read().split()
dir,file=os.path.split(input)
temp1 = os.path.join(dir,output1)
temp2 = os.path.join(dir,output2)
temp3 = os.path.join(dir,output3)
temp4 = os.path.join(dir,output4)
out_file4=open(temp4,'w')
random.shuffle(query)
for item in query:
out_file4.write(item+'\n')
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所以,如果总随机化文件是
example:
random_total = ['9','2','3','1','5','6','8','7','0','4']
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我想要3个文件(out_file1 | 2 | 3),第一个随机集3,第二个随机集3和第三个随机集3(对于这个例子,但我要创建的那个应该有50个)
random_1 = ['9','2','3']
random_2 = ['1','5','6']
random_3 = ['8','7','0']
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所以最后的'4'将不包括在内,这很好.
如何从随机化的列表中选择50?
更好的是,如何从原始列表中随机选择50?
Joh*_*ooy 231
如果列表是随机顺序,您可以选择前50个.
否则,请使用
import random
random.sample(the_list, 50)
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random.sample
帮助文字:
sample(self, population, k) method of random.Random instance
Chooses k unique random elements from a population sequence.
Returns a new list containing elements from the population while
leaving the original population unchanged. The resulting list is
in selection order so that all sub-slices will also be valid random
samples. This allows raffle winners (the sample) to be partitioned
into grand prize and second place winners (the subslices).
Members of the population need not be hashable or unique. If the
population contains repeats, then each occurrence is a possible
selection in the sample.
To choose a sample in a range of integers, use xrange as an argument.
This is especially fast and space efficient for sampling from a
large population: sample(xrange(10000000), 60)
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Man*_*ani 38
选择随机项的一种简单方法是随机播放然后切片.
import random
a = [1,2,3,4,5,6,7,8,9]
random.shuffle(a)
print a[:4] # prints 4 random variables
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Moe*_* MH 27
我认为这random.choice()
是一个更好的选择.
import numpy as np
mylist = [13,23,14,52,6,23]
np.random.choice(mylist, 3, replace=False)
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该函数返回列表中3个随机选择的值的数组
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