解码base64:输入无效

Question

试图在GNU/Linux上解码base64文件,我得到"base64:无效输入".

$ base64 test.zip | base64 -d > test2.zip
base64: invalid input
$ ll test*
-rw-r--r-- 1 user grp 152 19 11:41 test.zip
-rw-r--r-- 1 user grp  57 19 11:42 test2.zip

我尝试了dos2unix命令,但它没有帮助.

我的base64版本:

$ base64 --version
base64 (GNU coreutils) 5.97
Copyright (C) 2006 Free Software Foundation, Inc.
This is free software.  You may redistribute copies of it under the terms of
the GNU General Public License <http://www.gnu.org/licenses/gpl.html>.
There is NO WARRANTY, to the extent permitted by law.

Written by Simon Josefsson.

Answer 1

该版本不会解码(默认情况下)带分隔符的行,但编码器默认情况下会这样做.(较新版本没有此问题.)

一个解决方案

base64 -w 0 foo.zip | base64 -d > foo2.zip

备用:

base64 foo.zip | base64 -di > foo2.zip

该-i选项代表(从man页面):

-i, --ignore-garbage
       When decoding, ignore non-alphabet characters.
[...]
Decoding require compliant input by default, use --ignore-garbage to
attempt to recover from non-alphabet characters (such as newlines)

Answer 2

或者更简单

base64 -di foo.zip > foo2.zip