pyt*_*hor 4 c++ boost abstract-syntax-tree boost-spirit boost-spirit-qi
我正在尝试为数学表达式编写一个解析器,其中命名变量是boost::spirit(版本1_51_0)中的nullaries,我完全是新的.我定义typedef boost::function<double()> Value,我的规则将被声明如下:qi::rule<Iterator, Value()> expression, term, others, ...;
我用这个宏定义了nullaries上的二元运算符
#define BINARY_FUNCTOR(name, op) \
struct name \
{ \
name(Value x, Value y): x_(x), y_(y) {} \
double operator()() { return x_() op y_(); } \
Value x_, y_; \
};
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并且有ADD,SUB等从我所看到的例子,我期望的规则,这样的定义:
expression = term
>> *( (lit('+') >> term[ADD(_val, _1)])
| (lit('-') >> term[SUB(_val, _1)])
);
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但这似乎不是正确的语法,因为我得到一个错误
boost/spirit/home/support/action_dispatch.hpp:162: error: no match for call to ‘(const<unnamed>::SUB) (boost::function<double ()()>&, boost::spirit::context<boost::fusion::cons<boost::function<double ()()>&, boost::fusion::nil>, boost::fusion::vector0<void> >&, bool&)’
SRParser.cpp:38: note: candidates are: double<unnamed>::SUB::operator()()
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在我看来_1并不像我期望的那样,即Value与下一学期相关联.定义这样的规则的正确语法是什么?
解析器表达式看起来没问题.
你感到困惑的是构建AST.显然,你已经决定使用Semantic Actions来做到这一点,但是你的努力太过粗略,我无法看到(甚至决定你基于什么样本).
本质上:你想用"ADD"/"SUB"实例做什么,你似乎神奇地 "将"加入你的规则?
现在,您只需使用实例直接作为语义动作.这会导致显示的错误消息直接告诉您实例作为语义操作无效.
我假设您确实希望使用Phoenix赋值将二进制操作分配给公开的属性.这看起来像:
expression = term
>> *( (lit('+') >> term[ _val = phx::construct<ADD>(_val, _1)])
| (lit('-') >> term[ _val = phx::construct<SUB>(_val, _1)])
);
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你会发现这与传统的表达式语法更紧密地匹配.
为了好玩,我根据你的Value类型调整了一个完整的表达式解析器并创建了这个工作演示:http://liveworkspace.org/code/3kgPJR$0
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/karma.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace qi = boost::spirit::qi;
namespace karma = boost::spirit::karma;
namespace phx = boost::phoenix;
typedef std::function<double()> Value;
#define BINARY_FUNCTOR(name, op) \
struct name \
{ \
name(Value x, Value y): x_(x), y_(y) {} \
double operator()() { return x_() op y_(); } \
Value x_, y_; \
};
BINARY_FUNCTOR(ADD, +)
BINARY_FUNCTOR(SUB, -)
BINARY_FUNCTOR(MUL, *)
BINARY_FUNCTOR(DIV, /)
struct LIT
{
LIT(double x): x_(x) {}
double operator()() { return x_; }
double x_;
};
struct NEG
{
NEG(Value x): x_(x) {}
double operator()() { return -x_(); }
Value x_;
};
template <typename It, typename Skipper = qi::space_type>
struct parser : qi::grammar<It, Value(), Skipper>
{
parser() : parser::base_type(expression)
{
using namespace qi;
expression =
term [_val = _1]
>> *( ('+' >> term [_val = phx::construct<ADD>(_val, _1)])
| ('-' >> term [_val = phx::construct<SUB>(_val, _1)])
);
term =
factor [_val = _1]
>> *( ('*' >> factor [_val = phx::construct<MUL>(_val, _1)])
| ('/' >> factor [_val = phx::construct<DIV>(_val, _1)])
);
factor =
double_ [_val = phx::construct<LIT>(_1)]
| '(' >> expression [_val = _1] >> ')'
| ('-' >> factor [_val = phx::construct<NEG>(_1)])
| ('+' >> factor [_val = _1]);
BOOST_SPIRIT_DEBUG_NODE(expression);
BOOST_SPIRIT_DEBUG_NODE(term);
BOOST_SPIRIT_DEBUG_NODE(factor);
}
private:
qi::rule<It, Value(), Skipper> expression, term, factor;
};
Value doParse(const std::string& input)
{
typedef std::string::const_iterator It;
parser<It, qi::space_type> p;
Value eval;
auto f(begin(input)), l(end(input));
if (!qi::phrase_parse(f,l,p,qi::space,eval))
std::cerr << "parse failed: '" << std::string(f,l) << "'\n";
if (f!=l)
std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
return eval;
}
int main()
{
auto area = doParse("2 * (3.1415927 * (10*10))");
std::cout << "Area of a circle r=10: " << area() << "\n";
}
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它会打印出来
Area of a circle r=10: 628.319
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