ueg*_*990 1 java sql postgresql stored-procedures plpgsql
我编写了一个存储过程,我想用Java调用它.但我不认为它能够对我通过的查询做任何事情.以下是我的java代码:
String QUERY_LOCATION = "select (license_plate) as test from carInst( (select category_name from reservation where rid = ?) , (select lname from reservation where rid = ?))";
//PreparedStatement check_location = null;
PreparedStatement check_location = connection.prepareStatement(QUERY_LOCATION);
check_location.setInt(1, rid);
check_location.setInt(2, rid);
rs = check_location.executeQuery();
if (rs.next()) {
System.out.print("Car found: "+rs.getString("test")+"\n");
license_plate = rs.getString("test");
update_reservation.setString(5, license_plate);
bool = false;
} else {
System.out
.print("There is no car available\n");
}
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以下是我用PL/pgSQL(PostgreSQL)编写的存储过程:
CREATE OR REPLACE FUNCTION carInst(cname varchar(20), loc varchar(20) )
RETURNS TABLE (license_plate varchar(6) ) AS $$
BEGIN
DECLARE cur CURSOR
FOR SELECT carinstance.license_plate, carmodel.category_name, carinstance.lname FROM carinstance,carmodel
WHERE carinstance.mid = carmodel.mid ;
BEGIN
FOR rec IN cur LOOP
RETURN QUERY SELECT distinct carinstance.license_plate FROM Carinstance
WHERE rec.category_name = cname
AND rec.lname = loc
AND rec.license_plate=carinstance.license_plate;
END LOOP;
END;
END;
$$ LANGUAGE plpgsql;
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当我在Java中运行代码时,print语句为Car found打印一个空值.我真的很感激这里的一些帮助.
最重要的是,查询中的LOOP含义是无稽之谈.您可以从中选择行carinstance,但所有条件都已启用rec.这会多次选择所有行.
一个END太多了.FOR没有END,只有LOOP.
每当你感觉到在plpgsql中使用显式游标的诱惑时,请在那里停下来.机会是,你做错了.一个FOR循环有一个隐式游标反正.
不要在没有双引号的情况下混淆大小写标识符.我将所有标识符转换为小写.
您使用一个简单的查询,分散在游标和另一个查询上.这一切都可以简单得多.
请尝试使用这个简单的SQL函数:
CREATE OR REPLACE FUNCTION car_inst(_cname text, _loc text)
RETURNS TABLE (license_plate text) AS
$func$
SELECT DISTINCT ci.license_plate
FROM carmodel cm
JOIN carinstance ci USING (mid)
WHERE cm.category_name = $1
AND ci.lname = $2
$func$ LANGUAGE sql;
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呼叫:
"SELECT license_plate AS test FROM car_inst(
(SELECT category_name FROM reservation WHERE rid = ?)
,(SELECT lname FROM reservation WHERE rid = ?))";
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或者将它全部构建到您的函数中:
CREATE OR REPLACE FUNCTION car_inst(_cname text, _loc text)
RETURNS TABLE (license_plate text) AS
$func$
SELECT DISTINCT ci.license_plate
FROM carmodel cm
JOIN carinstance ci USING (mid)
JOIN reservation r1 ON r1.category_name = cm.category_name
JOIN reservation r2 ON r2.lname = ci.lname
WHERE r1.rid = $1
AND r2.rid = $2;
$func$ LANGUAGE sql;
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呼叫:
"SELECT license_plate AS test FROM car_inst(? , ?)";
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请记住:该OUT参数license_plate在函数体中的任何位置都可见.因此,您必须始终对同名列进行表限定,以防止命名冲突.
DISTINCT 可能是也可能不是多余的.