用于存储重复事件的数据结构？


.---------------- minute (0 - 59) 
|  .------------- hour (0 - 23)
|  |  .---------- day of month (1 - 31)
|  |  |  .------- month (1 - 12) OR jan,feb,mar,apr ... 
|  |  |  |  .---- day of week (0 - 6) (Sunday=0 or 7)  OR sun,mon,tue,wed,thu,fri,sat 
|  |  |  |  |
*  *  *  *  * 

There are several special entries, most of which are just shortcuts, 
that can be used instead of specifying the full cron entry:

Entry      Description                 Equivalent To
@reboot    Run once, at startup.       None
@yearly    Run once a year             0 0 1 1 *
@annually  (same as @yearly)           0 0 1 1 *
@monthly   Run once a month            0 0 1 * *
@weekly    Run once a week             0 0 * * 0
@daily     Run once a day              0 0 * * *
@midnight  (same as @daily)            0 0 * * *
@hourly    Run once an hour            0 * * * *

Answer 3

Dan*_*rod 6

Event:

StartDate
EndDate (calculated on change of NumberOfOccurances)
NumberOfOccurances (calculated on change of EndDate )
Frequency e.g. 1/2hrs, 1/month, 1/day, ....
CorrectionFunction e.g. first Tuesday, last Sunday, ...

bool OccuresOn(day)
Date NextOccurance(date)

Answer 4

Dan*_*n B 5

这是我的看法 - 请告诉我,如果我遗漏了什么:

根据Outlook Recurrence选项,您有一个包含常规必填字段的表:

FieldName       DataType      Sample Data
ID              int           primary key
EventID         int           foreign key (to EventID from Event Table)
StartTime       DateTime      8:00 AM
EndTime         DateTime      8:30 AM
Duration        int           30 (minutes)
StartDate       DateTime      01/25/2014
EndBy           DateTime      01/25/2024
NoEndDate       bit           False
NumOccurrences  int           10
RecurrenceType  int           ****See below for instructions on how to use these last 6 fields  
Int1            int           
Int2            int
Int3            int
String1         nvarchar(50)
IntYears        int

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这是神奇发生的地方.这个逻辑只需要4个整数和一个字符串.

The month of year (1 = Jan, 12 = Dec), 
The day of the month (1 = the 1st, 31 = 31st), 
Day of the week (0 = Sunday, 1=Monday, 6= Saturday), 
Week of the month (1 = first, 4 = forth, 5 = last),
Yearly reocurrence ( 1=1,2=2)   
When multiple days can be selected I use a comma delimited string (1,3,5 = Monday, Wed, Friday)

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我按照它们出现在outlook Appointment Recurrence调度程序中的顺序输入3个整数,这样可以节省额外的费用,逻辑,烦恼. *如果您打开outlook appt调度程序,这将更容易遵循:

The RecurrenceType field can be any of the 7 following choices

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(每日,每月和每年有2个选项,每周有一个选项):

10 = Daily (Every `Int1` day(s) )    
            Every     4  day(s)
11 = Daily (Every Weekday)  -- no variables needed 
            Every Weekday (MTWTF)
20 = Weekly (Recur every `Int1` week(s) on: `String1`
             Recur every     3  week(s) on  Monday, Wednesday, Friday   
(`String1` will be a list of days selected (0=Sunday, 1=Monday, 2=Tuesday... 7=Saturday) so for (Mon, Wed, Fri) String1 would hold "1,3,5". You would parse this on the code side to pull the actual days.)
30 = Monthly (Day `Int1` of every `int2' month(s) 
              Day    28  of every     2  month(s)
31 = Monthly (The `Int1`  `Int2` of every `Int3` month(s) 
              The forth Tuesday  of every     1  month(s)
40 = Yearly (Recur every `intYears` year(s) On `Int1` `Int2`) -- 
             Recur every         1  year(s) on   Jan   28th
41 = Yearly (Recur every `intYears` year(s) on the `Int1` `Int2` of `Int3`) -- 
             Recur every         1  year(s) on the forth Tuesday of January

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拉动或保存重复的代码变得相当简单

if (RecurrenceType = 10 )
    Every `int1` days
if (RecurrenceType = 11)
    Every Weekday
if (RecurrenceType = 20)
    Every `int1 weeks on 
    parse `string1` and populate checkboxes for Mon, Tues, ...
if (RecurrenceType = 30)
    `int1 day of every `int2` month

etc...

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我希望我能够彻底解释这一点.如果有什么不清楚或是否不起作用,请告诉我.我正在为当前的应用程序构建此功能.谢谢大家.

嘿！很好的答案！这给我留下了一个悬而未决的问题：是否有一种快速的方法可以计算开始日期和结束日期之间的所有日期，而无需迭代每个日期？ (2认同)

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