如何使用GGPLOT创建分面相关图

nev*_*int 5 plot r ggplot2

我有一个以下面的方式创建的数据框.

library(ggplot2)

x <- data.frame(letters[1:10],abs(rnorm(10)),abs(rnorm(10)),type="x")
y <- data.frame(letters[1:10],abs(rnorm(10)),abs(rnorm(10)),type="y")
 # in reality the number of row could be larger than 10 for each x and y

all <- rbind(x,y)
colnames(all) <- c("name","val1","val2","type")
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我想要做的是创建一个看起来大致如下的刻面ggplot:

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因此,上面的每个方面都是以下相关图:

# Top left facet
subset(all,type=="x")$val1 
subset(all,type=="y")$val1

# Top right facet
subset(all,type=="x")$val1 
subset(all,type=="y")$val2

# ...etc..
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但我坚持使用以下代码:

p <- ggplot(all, aes(val1, val2))+ geom_smooth(method = "lm")  + geom_point() +
facet_grid(type ~ ) 
# Calculate correlation for each group
cors <- ddply(all, c(type ~ ), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=0.5, y=0.5)
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什么是正确的方法呢?

ale*_*han 8

你的一些代码不正确.这对我有用:

p <- ggplot(all, aes(val1, val2))+ geom_smooth(method = "lm")  + geom_point() +
  facet_grid(~type) 
# Calculate correlation for each group
cors <- ddply(all, .(type), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=1, y=-0.25)
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编辑:关注 OP的评论和编辑.我们的想法是用所有四种组合重新创建数据,然后再进行分面.

# I consider the type in your previous data to be xx and yy
dat <- data.frame(val1 = c(rep(all$val1[all$type == "x"], 2), 
                           rep(all$val1[all$type == "y"], 2)), 
                  val2 = rep(all$val2, 2), 
                  grp1 = rep(c("x", "x", "y", "y"), each=10), 
                  grp2 = rep(c("x", "y", "x", "y"), each=10))

p <- ggplot(dat, aes(val1, val2)) + geom_point() + geom_smooth(method = "lm") + 
     facet_grid(grp1 ~ grp2)
cors <- ddply(dat, .(grp1, grp2), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=1, y=-0.25)
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在此输入图像描述

  • 所以你想在对角线上做什么?在哪里说'不需要绘图' - 但它是在你的图表中绘制的? (3认同)