我有一个以下面的方式创建的数据框.
library(ggplot2)
x <- data.frame(letters[1:10],abs(rnorm(10)),abs(rnorm(10)),type="x")
y <- data.frame(letters[1:10],abs(rnorm(10)),abs(rnorm(10)),type="y")
# in reality the number of row could be larger than 10 for each x and y
all <- rbind(x,y)
colnames(all) <- c("name","val1","val2","type")
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我想要做的是创建一个看起来大致如下的刻面ggplot:
因此,上面的每个方面都是以下相关图:
# Top left facet
subset(all,type=="x")$val1
subset(all,type=="y")$val1
# Top right facet
subset(all,type=="x")$val1
subset(all,type=="y")$val2
# ...etc..
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但我坚持使用以下代码:
p <- ggplot(all, aes(val1, val2))+ geom_smooth(method = "lm") + geom_point() +
facet_grid(type ~ )
# Calculate correlation for each group
cors <- ddply(all, c(type ~ ), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=0.5, y=0.5)
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什么是正确的方法呢?
你的一些代码不正确.这对我有用:
p <- ggplot(all, aes(val1, val2))+ geom_smooth(method = "lm") + geom_point() +
facet_grid(~type)
# Calculate correlation for each group
cors <- ddply(all, .(type), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=1, y=-0.25)
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编辑:关注 OP的评论和编辑.我们的想法是用所有四种组合重新创建数据,然后再进行分面.
# I consider the type in your previous data to be xx and yy
dat <- data.frame(val1 = c(rep(all$val1[all$type == "x"], 2),
rep(all$val1[all$type == "y"], 2)),
val2 = rep(all$val2, 2),
grp1 = rep(c("x", "x", "y", "y"), each=10),
grp2 = rep(c("x", "y", "x", "y"), each=10))
p <- ggplot(dat, aes(val1, val2)) + geom_point() + geom_smooth(method = "lm") +
facet_grid(grp1 ~ grp2)
cors <- ddply(dat, .(grp1, grp2), summarise, cor = round(cor(val1, val2), 2))
p + geom_text(data=cors, aes(label=paste("r=", cor, sep="")), x=1, y=-0.25)
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