从JSON对象中删除元素

Question

我有一个json数组,看起来像这样:

  {
    "id": 1,
    "children": [
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    }]
}

我想有一个函数删除"子"空的元素.我该怎么做？我不是要求答案,只是建议

Answer 1

要遍历对象的键,请使用for .. in循环:

for (var key in json_obj) {
    if (json_obj.hasOwnProperty(key)) {
        // do something with `key'
    }
}

要测试空子项的所有元素,可以使用递归方法:遍历所有元素并递归测试它们的子项.

可以使用以下delete关键字删除对象的属性:

var someObj = {
    "one": 123,
    "two": 345
};
var key = "one";
delete someObj[key];
console.log(someObj); // prints { "two": 345 }

文档:

• https://developer.mozilla.org/en-US/docs/JavaScript/Guide/Working_with_Objects
• https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Statements/for...in
• https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Operators/delete