Django'function'对象没有属性'对象'

Question

我的应用程序允许您喜欢图片然后将您重定向到同一页面

当我尝试想要一张图片时我得到错误我可以用shell提示创建一个类似的对象,但为什么我会收到此错误？谢谢你的帮助

AttributeError at /like/3/
function' object has no attribute 'objects'Request Method: GET 
Request URL: http://127.0.0.1:8000/like/3/ 

Exception Value: 'function' object has no attribute 'objects' 
Traceback:
File "C:\Python26\Lib\site-packages\django\core\handlers\base.py" in get_response
111.                         response = callback(request, *callback_args, **callback_kwargs)
File "C:\o\mysite\pet\views.py" in Like
195.     new_like, created = Like.objects.get_or_create(user=request.user, picture_id=picture_id)

这是我的views.py的一部分

def Like(request,picture_id):
    pid = picture_id
    new_like, created = Like.objects.get_or_create(user=request.user, picture_id=picture_id)
    p = Picture.objects.get(pk=pid)
    if created:
        HttpResponseRedirect(reverse('world:url_name'))
    else:
        HttpResponseRedirect(reverse('world:url_name'))

我的URLconf:

     url(

我的模特的部分:r'^ like /(？P\d +)/ $','pet.views.Like',name ='Like'),我的boat.html

 {% if picture %}
 <ul>
    {% for pet in picture %}
    <li><b>description</b> = {{ pet.description}}<br/>
        {% if pet.image %}
 <li>
    <a href ="{% url world:Like pet.id %}">
        <img src= "{{ pet.image.url }}" style="cursor:pointer">
    </a>
 <li>
        {% endif %}
 {% endfor %}
 </ul>
 {% endif %}
 <a href="{% url world:PictureCreator %}">Add Pictures to your board</a><br/>

我的models.py

class Picture(models.Model):
    user = models.ForeignKey(User)
    board = models.ForeignKey(Board,blank=False,null=False)
    image = models.FileField(upload_to="images/",blank=True)
    description = models.TextField()
    is_primary = models.BooleanField(default=False)
    def __unicode__(self):
        return self.description

class Like(models.Model):
    user = models.ForeignKey(User)
    picture = models.ForeignKey(Picture)
    created = models.DateTimeField(auto_now_add=True)    

Answer 1

您的视图函数名称定义为,Like并且您的模型已命名Like

你定义Like为一个函数,所以当你去访问Like.objectspython 时,你看不到你的模型Like而是函数Like

你可以重命名你的视图功能

url(r'^like/(?P\d+)/$', 'pet.views.change_name_no_conflict', name = 'Like' )


def change_name_no_conflict(request,picture_id):
  pass

Answer 2

模型名称和视图名称不应相同。