如何处理下载的json字符串?

use*_*781 1 python tkinter

我有一个json字符串,我试图通过使用tkinter GUI窗口上的标签打印每个部分(id,名称,链接等).

数据:

{"id":"123456789","name":"John Smith","first_name":"John","last_name":"Smith","link":"http:\/\/www.facebook.com\/john.smith","username":"john.smith","gender":"male","locale":"en_GB"}
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码:

URL = https://graph.facebook.com/ + user
info = urlopen(info).read()
json_format = infor.decode("utf-8")
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我的问题是如何将json数据的每个部分分配给变量,它是否可以在tkinter标签上打印出来?

提前致谢

编辑

试过这段代码:

jsonData = json.loads(json_format)
u_name = jsoninfo['username']
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并收到以下错误消息

TypeError: string indices must be integers
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ice*_*ime 6

您想使用json标准模块:

>>> import json
>>> data = '{"id":"123456789","name":"John Smith","first_name":"John","last_name":"Smith","link":"http:\/\/www.facebook.com\/john.smith","username":"john.smith","gender":"male","locale":"en_GB"}'
>>> d = json.loads(data)
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这会将您的数据作为常用字典使用:

>>> d
{u'username': u'john.smith', u'first_name': u'John', u'last_name': u'Smith', u'name': u'John Smith', u'locale': u'en_GB', u'gender': u'male', u'link': u'http://www.facebook.com/john.smith', u'id': u'123456789'}
>>> d['username']
u'john.smith'
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