将位图保存到文件中并返回具有位图图像的文件

And*_*diM 17 android

我有一个问题是将位图保存到文件中.我的方法是这样的:

private File savebitmap(Bitmap bmp) {
    String extStorageDirectory = Environment.getExternalStorageDirectory()
            .toString();
    OutputStream outStream = null;

    File file = new File(bmp + ".png");
    if (file.exists()) {
        file.delete();
        file = new File(extStorageDirectory, bmp + ".png");
        Log.e("file exist", "" + file + ",Bitmap= " + bmp);
    }
    try {
        outStream = new FileOutputStream(file);
        bmp.compress(Bitmap.CompressFormat.PNG, 100, outStream);
        outStream.flush();
        outStream.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
    Log.e("file", "" + file);
    return file;

}
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它给了我file的错误.我这样调用这个方法:

Drawable d = iv.getDrawable();
Bitmap bitmap = ((BitmapDrawable) d).getBitmap();
File file = savebitmap(bitmap);
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请帮我...

Fes*_*loe 34

我尝试对您的代码进行一些更正我假设您要使用filename而不是位图作为参数

 private File savebitmap(String filename) {
      String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
      OutputStream outStream = null;

      File file = new File(filename + ".png");
      if (file.exists()) {
         file.delete();
         file = new File(extStorageDirectory, filename + ".png");
         Log.e("file exist", "" + file + ",Bitmap= " + filename);
      }
      try {
         // make a new bitmap from your file
         Bitmap bitmap = BitmapFactory.decodeFile(file.getName());

         outStream = new FileOutputStream(file);
         bitmap.compress(Bitmap.CompressFormat.PNG, 100, outStream);
         outStream.flush();
         outStream.close();
      } catch (Exception e) {
         e.printStackTrace();
      }
      Log.e("file", "" + file);
      return file;

   }
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