Spring REST-ful uri带有可选的查询字符串

Question

触发默认控制器以获取所有汽车的普通uri只是"/ cars"

我希望能够搜索汽车以及uri,例如:"/ cars？model = xyz",它将返回匹配汽车列表.所有请求参数都应该是可选的.

问题是,即使使用查询字符串,默认控制器仍会触发,我总是得到"所有汽车:......"

有没有办法用Spring做这个没有单独的搜索uri(比如"/ cars/search？..")？

码:

@Controller
@RequestMapping("/cars")
public class CarController {
@Autowired
private CarDao carDao;

@RequestMapping(method = RequestMethod.GET, value = "?")
public final @ResponseBody String find(
        @RequestParam(value = "reg", required = false) String reg,
        @RequestParam(value = "model", required = false) String model
        )
{
    Car searchForCar = new Car();
    searchForCar.setModel(model);
    searchForCar.setReg(reg);
    return "found: " + carDao.findCar(searchForCar).toString();
}

@RequestMapping(method = RequestMethod.GET)
public final @ResponseBody String getAll() {
    return "all cars: " + carDao.getAllCars().toString();
} 
}

Answer 1

您可以使用

@RequestMapping(method = RequestMethod.GET, params = {/* string array of params required */})
public final @ResponseBody String find(@RequestParam(value = "reg") String reg, @RequestParam(value = "model") String model)
    // logic
}

即,@RequestMapping注释具有一个名为的属性params.如果您指定的所有参数都包含在您的请求中(并且所有其他RequestMapping要求都匹配),那么将调用该方法.