如何使fmt.Scanln()读入整数切片

Question

我有一行包含3个数字,我想从stdin用fmt.Scanln()读取,但这段代码不起作用:

X := make([]int, 3)
fmt.Scanln(X...)
fmt.Printf("%v\n", X)

我收到此错误消息:

cannot use X (type []int) as type []interface {} in function argument

我不明白.

Answer 1

惯用Go将是:

func read(n int) ([]int, error) {
  in := make([]int, n)
  for i := range in {
    _, err := fmt.Scan(&in[i])
    if err != nil {
       return in[:i], err
    }
  }
  return in, nil
}

interface{}没意思.如果您不需要,请不要使用它.

Answer 2

例如,

package main

import "fmt"

func intScanln(n int) ([]int, error) {
    x := make([]int, n)
    y := make([]interface{}, len(x))
    for i := range x {
        y[i] = &x[i]
    }
    n, err := fmt.Scanln(y...)
    x = x[:n]
    return x, err
}

func main() {
    x, err := intScanln(3)
    if err != nil {
        fmt.Println(err)
        return
    }
    fmt.Printf("%v\n", x)
}

输入:

1 2 3

输出:

[1 2 3]