Yii - Cdbcriteria - 选择具有关系的条件之间的运算符

Ric*_*ani 2 php mysql yii

我遇到了以下问题.我只想显示已插入任务本身或负责任务的人员,为此,我有以下数据库架构:

表Funcionario(员工表)= id,name等...

表TarefasGerais(任务表)= id,id_funcionario(插入它)等等...

表TarefasResponsaveis(负责雇员表)= id,id_tarefa(tarefas gerais id),id_funcionario(雇员id)

在我的模型的搜索方法中,我做了以下内容:

    $criteria->with = array('Responsaveis' => 
        array('condition' => 'Responsaveis.id_funcionario = ' . Yii::app()->user->dados->id));
    $criteria->condition = 'id_funcionario_lancamento = ' . Yii::app()->user->dados->id;
Run Code Online (Sandbox Code Playgroud)

但它会生成以下SQL:

    SELECT COUNT(DISTINCT `t`.`id`) FROM `tbl_tarefas_gerais` `t` LEFT OUTER JOIN `tbl_tarefas_gerais_responsaveis` `Responsaveis` ON
    (`Responsaveis`.`id_tarefa` = `t`.`id`) WHERE (id_funcionario_lancamento =
    3) AND (Responsaveis.id_funcionario = 3)
Run Code Online (Sandbox Code Playgroud)

如你所见,它使用"AND"运算符,但我需要它在where部分使用"OR"运算符.

我试过了 :

    $criteria->with = array('Responsaveis' =>
        array('condition' => 'Responsaveis.id_funcionario = ' . Yii::app()->user->dados->id, 'operator' => 'OR'));
Run Code Online (Sandbox Code Playgroud)

但它没有改变任何东西.

有没有人知道如何处理?

干杯0 /

dev*_*ooh 5

尝试mergeWith两个标准.

将您的逻辑分为两个标准并将它们合并在一起

$criteria->with = array('Responsaveis' => 
    array('condition' => 'Responsaveis.id_funcionario = ' . Yii::app()->user->dados->id));
$criteria2->condition = 'id_funcionario_lancamento = ' . Yii::app()->user->dados->id;
$criteria->mergeWith($criteria2);
Run Code Online (Sandbox Code Playgroud)

完整示例:

$criteria2 = new CDbCriteria();
$criteria2->addInCondition('startDate', array(null));
$criteria2->addBetweenCondition('startDate', date('Y-m-d'), '1950-01-01', 'OR');

$criteria3 = new CDbCriteria();
$criteria3->addInCondition('stopDate', array(null), 'AND');
$criteria3->addBetweenCondition('stopDate', '1990-01-01', date('Y-m-d'), 'OR');

$criteria3->mergeWith($criteria2);
Run Code Online (Sandbox Code Playgroud)