将XML反序列化为对象 - XML文档中存在错误(0,0)

DGi*_*bbs 7 .net c# xml serialization

我正在尝试从简单的XML文档读取元素值并将它们绑定到一个对象,但是我遇到了我的XML文档的问题.我已经验证了它,并且可以确认文档本身没有问题,但是扩展了结果:

var nodes = from xDoc in xml.Descendants("RewriteRule")
                select xmlSerializer.Deserialize(xml.CreateReader()) as Url;
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显示"XML文档中存在错误(0,0)"

内部异常读取 <RewriteRules xmlns=''> was not expected.

我不确定我在这里做错了什么?

我的XML如下:

<?xml version="1.0" encoding="utf-8" ?>
<RewriteRules>
    <RewriteRule>
        <From>fromurl</From>
        <To>tourl</To>
        <Type>301</Type>
    </RewriteRule>
</RewriteRules>
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加载XML文件并尝试对其进行反序列化的代码: -

public static UrlCollection GetRewriteXML(string fileName)
{
    XDocument xml = XDocument.Load(HttpContext.Current.Server.MapPath(fileName));
    var xmlSerializer = new XmlSerializer(typeof(Url));

    var nodes = from xDoc in xml.Descendants("RewriteRule")
                select xmlSerializer.Deserialize(xml.CreateReader()) as Url;

    return nodes as UrlCollection;
}
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我的Url对象类: -

[Serializable]
[XmlRoot("RewriteRule")]
public class Url
{
    [XmlElement("From")]
    public string From { get; set; }
    [XmlElement("To")]
    public string To { get; set; }
    [XmlElement("Type")]
    public string StatusCode { get; set; }

    public Url()
    {
    }

    public Url(Url url)
    {
        url.From = this.From;
        url.To = this.To;
        url.StatusCode = this.StatusCode;
    }
}
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谁能看到我在这里做错了什么?

谢谢

Def*_*ult 4

我对这个声明不太熟悉from select,但似乎你只是传递了xmlwhich is the full XDocument,而不是 the XElementthat is your RewriteRule。这就是为什么您会收到未知的错误消息RewriteRules-XmlSerializer需要一个RewriteRule.

我设法使用 相反 重写您的代码LINQ(但如果您知道如何从from select语句中获取单个元素,那应该同样有效)。

这应该给你正确的结果 -rrXElement从返回的Descendants

public static IEnumerable<Url> GetRewriteXML()
{
    XDocument xml = XDocument.Load(HttpContext.Current.Server.MapPath(fileName));

    var xmlSerializer = new XmlSerializer(typeof(Url));

    var nodes = xml.Descendants("RewriteRule")
                .Select(rr => xmlSerializer.Deserialize(rr.CreateReader()) as Url);

    return nodes;
}
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