typ*_*ype 34 python version argparse
在argparse中指定程序名称和版本信息的首选方法是什么?
__version_info__ = ('2013','03','14')
__version__ = '-'.join(__version_info__)
...
parser.add_argument('-V', '--version', action='version', version="%(prog)s ("+__version__+")")
eca*_*mur 64
是的,这是公认的方式.来自http://docs.python.org/dev/library/argparse.html#action:
>>> parser.add_argument('--version', action='version', version='%(prog)s 2.0')
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您当然应该以标准方式将版本号嵌入到包中:将版本嵌入到python包中的标准方法是什么?
如果您正在使用该方法,则您有一个__version__变量:
from _version import __version__
parser.add_argument('--version', action='version',
version='%(prog)s {version}'.format(version=__version__))
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例如,这是在https://pypi.python.org/pypi/commando/0.3.2a上演示的方法:
Run Code Online (Sandbox Code Playgroud)parser.add_argument('-v', '--version', action='version', version='%(prog)s ' + __version__)
Just wanted to post another approach. As of Python 3.11, you can get a package's version number as a string using importlib.metadata. So if your program is a package with a pyproject.toml file then you can get the version number that is defined in that file. The example below get's the version string of a command line tool named genja; where genja is the name of the Python package that is the command line program.
from importlib.metadata import version
parser.add_argument('-v', '--version', action='version', version=version('genja'))
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