Omn*_*Owl 6 c# stack-overflow recursion
我目前正在编写一个程序来帮助编写Lore.每个图书对象都可以是父母并且有孩子.这意味着每个孩子都可以有孩子等无限.我正在使用ToString()方法,可以使用递归来解决这个问题,但我不断得到StackOverflowException.
我知道这意味着什么,但我对如何解决这个问题表示怀疑.我是C#的新手,但有很多Java经验,所以如果你知道一些我错过的技巧或者其他东西,请告诉我!
所以我的问题是:如何避免StackOverflow异常?问题出在GetAllChildren()
编辑:
运行测试后,我应该得到这样的东西:
Name: a
Children:
b
c
d
e
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使用@lc的代码.我得到以下输出:
Name: a
Children: No Children b
c
e
b
c
e
b
c
e
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这是班级:
class Book
{
private String name;
private Book[] children;
private StringBuilder text;
private Boolean isParent;
public Book(String name, Book[] children, StringBuilder text, Boolean isParent)
{
this.name = name;
this.children = children;
this.text = text;
this.isParent = isParent;
}
/**
* Most likely all possible Constructors
* */
public Book(String name, Book[] children) : this(name, children, new StringBuilder("No Text"), true) { }
public Book(String name, String text) : this(name, new Book[0], new StringBuilder(text), false) { }
public Book(String name, StringBuilder text) : this(name, new Book[0], text, false) { }
public Book(String name) : this(name, new Book[0], new StringBuilder("No Text"), false) { }
public Book(Book[] children, String text) : this("Unnamed Book", children, new StringBuilder(text), true) { }
public Book(Book[] children, StringBuilder text) : this("Unnamed Book", children, text, true) { }
public Book(Book[] children) : this("Unnamed Book", children, new StringBuilder("No Text"), true) { }
public Book(StringBuilder text) : this("Unnamed Book", new Book[0], text, false) { }
public Book() : this("Unnamed Book", new Book[0], new StringBuilder("No Text"), false) { }
public String Name
{
get { return name; }
set { name = value; }
}
public Book[] Children
{
get { return children; }
set { children = value; }
}
/**
* Will Return the StringBuilder Object of this Text
* */
public StringBuilder Text
{
get { return text; }
set { text = value; }
}
public Boolean IsParent
{
get { return isParent; }
set { isParent = value; }
}
private void GetAllChildren(Book book, StringBuilder sb)
{
if (book.isParent)
{
GetAllChildren(book, sb);
}
else
{
sb.Append("\t");
foreach (Book b in children)
{
sb.Append(b.Name + "\n");
}
}
}
public override String ToString()
{
StringBuilder sChildren = new StringBuilder("No Children");
if (children.Length != 0)
{
GetAllChildren(this, sChildren);
}
return "Name: " + name + "\n" +
"Children: " + sChildren.ToString();
}
}
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我想你的意思是:
if (book.isParent)
{
foreach (var child in book.Children)
GetAllChildren(child, sb);
}
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否则你只是反复调用GetAllChildren具有相同参数(book, sb)的方法.
旁注 - 你仍然有一些问题,因为GetAllChildren正在迭代通过子节点的停止条件,当它不应该(如果它不是父节点,它不应该有子节点).它应该返回自己的名称.此外,每个孩子还应在上面的foreach循环中附加其名称(实际上,每本书都应附加自己的名字).
附注2 - 编写的方法(带有这些更改)应该是静态的,因为它与任何给定的实例无关(这使我得到下面的建议).
建议 - 我会推荐类似下面的东西(未经测试,需要对格式化工作):
//name changed to reflect what it really does
//also changed to be an instance method (we no longer pass in a Book)
//added listThisBooksName parameter to allow supressing the topmost book's output
private void AppendAllChildren(StringBuilder sb, int level = 0,
bool listThisBooksName = false)
{
if (listThisBooksName)
{
//append ourself here
//first indent however far we need to
sb.Append(new String('\t', level));
//now add our name
sb.Append(this.Name);
//and a newline (you can strip the last one later if you want)
sb.Append('\n');
}
//forget the "isParent" property, just check if it has any children
//we don't need Children.Any() because the foreach will just iterate 0 times
//you might also consider using a List<Book> instead of an array for Children
if (this.Children != null)
foreach (var child in this.Children)
child.AppendAllChildren(sb, level+1, true);
}
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