计算python字典中值的重复

Question

我有一个以下格式的字典.在这本词典中,存在不同种类的区域,但是存在多次.我想从此生成另一个字典,其中包含一个附加键"Count",该键将包含重复区域(即"Full Run"或"Half Run"或"Semi Run")的次数.

[
{'zip_zone': u'Full Run', 'zipcode': u'14042', 'longitude': -78.516154}, 
{'zip_zone': u'Full Run', 'zipcode': u'14101', 'longitude': -78.51734}, 
{'zip_zone': u'Full Run', 'zipcode': u'14706', 'longitude': -78.493761}, 
{'zip_zone': u'Half Run', 'zipcode': u'14709', 'longitude': -78.024817}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14711', 'longitude': -78.119974}, 
{'zip_zone': u'Full Run', 'zipcode': u'14714', 'longitude': -78.256921}, 
{'zip_zone': u'Half Run', 'zipcode': u'14715', 'longitude': -78.157392}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14717', 'longitude': -78.210567}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14719', 'longitude': -78.86951}, 
{'zip_zone': u'Half Run', 'zipcode': u'14727', 'longitude': -78.268103}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14731', 'longitude': -78.658909}, 
{'zip_zone': u'Half Run', 'zipcode': u'14735', 'longitude': -78.087607}, 
{'zip_zone': None, 'zipcode': u'14737', 'longitude': -78.431625}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14739', 'longitude': -78.139046}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14741', 'longitude': -78.5907}, 
{'zip_zone': u'Special Run', 'zipcode': u'14743', 'longitude': -78.4098}, 
{'zip_zone': u'Special Run', 'zipcode': u'14744', 'longitude': -78.167853}, 
{'zip_zone': u'Half Run', 'zipcode': u'14748', 'longitude': -78.639987}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14753', 'longitude': -78.640416}, 
{'zip_zone': u'Special Run', 'zipcode': u'14754', 'longitude': -78.18395}, 
{'zip_zone': u'Special Run', 'zipcode': u'14755', 'longitude': -78.800866}, 
{'zip_zone': u'Half Run', 'zipcode': u'14760', 'longitude': -78.426015}, 
]

输出字典应该是这样的

[
{'zip_zone': u'Full Run', 'zipcode': u'14042', 'longitude': -78.516154, 'count': 4}, 
{'zip_zone': u'Full Run', 'zipcode': u'14101', 'longitude': -78.51734, 'count': 4}, 
{'zip_zone': u'Full Run', 'zipcode': u'14706', 'longitude': -78.493761, 'count': 4}, 
{'zip_zone': u'Half Run', 'zipcode': u'14709', 'longitude': -78.024817, 'count': 6}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14711', 'longitude': -78.119974, 'count': 7}, 
{'zip_zone': u'Full Run', 'zipcode': u'14714', 'longitude': -78.256921, 'count': 4}, 
{'zip_zone': u'Half Run', 'zipcode': u'14715', 'longitude': -78.157392, 'count': 6}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14717', 'longitude': -78.210567, 'count': 7}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14719', 'longitude': -78.86951, 'count': 7}, 
{'zip_zone': u'Half Run', 'zipcode': u'14727', 'longitude': -78.268103, 'count': 6}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14731', 'longitude': -78.658909, 'count': 7}, 
{'zip_zone': u'Half Run', 'zipcode': u'14735', 'longitude': -78.087607, 'count': 6}, 
{'zip_zone': None, 'zipcode': u'14737', 'longitude': -78.431625, 'count': 0}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14739', 'longitude': -78.139046, 'count': 7}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14741', 'longitude': -78.5907, 'count': 7}, 
{'zip_zone': u'Special Run', 'zipcode': u'14743', 'longitude': -78.4098, 'count': 4}, 
{'zip_zone': u'Special Run', 'zipcode': u'14744', 'longitude': -78.167853, 'count': 4}, 
{'zip_zone': u'Half Run', 'zipcode': u'14748', 'longitude': -78.639987, 'count': 6}, 
{'zip_zone': u'Semi Run', 'zipcode': u'14753', 'longitude': -78.640416, 'count': 7}, 
{'zip_zone': u'Special Run', 'zipcode': u'14754', 'longitude': -78.18395, 'count': 4}, 
{'zip_zone': u'Special Run', 'zipcode': u'14755', 'longitude': -78.800866, 'count': 4}, 
{'zip_zone': u'Half Run', 'zipcode': u'14760', 'longitude': -78.426015, 'count': 6}, 
]

Answer 1

这是Python集合模块中Counter类的一个很好的用例.

import collections

# u is your input list of dictionaries, entries in u will be modified in place

c = collections.Counter(e["zip_zone"] for e in u)
for e in u:
    e["count"] = c[e["zip_zone"]]