Lau*_*per 73 mysql sql insert exists
我想要做的是INSERT我的数据库中的订阅者,但IF EXISTS它应该UPDATE是行,ELSE INSERT INTO一个新行.
Ofcourse我连接到数据库第一和GET的$name,$email并$birthday从URL字符串.
$con=mysqli_connect("localhost","---","---","---");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$name=$_GET['name'];
$email=$_GET['email'];
$birthday=$_GET['birthday'];
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这可行,但只是添加新行;
mysqli_query($con,"INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES ('$name', '$email', '$birthday')");
mysqli_close($con);
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这是我尝试过的;
mysqli_query($con,"INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES '$name', '$email', '$birthday'
ON DUPLICATE KEY UPDATE subs_name = VALUES($name), subs_birthday = VALUES($birthday)");
mysqli_close($con);
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和
mysqli_query($con,"IF EXISTS (SELECT * FROM subs WHERE subs_email='$email')
UPDATE subs SET subs_name='$name', subs_birthday='$birthday' WHERE subs_email='$email'
ELSE
INSERT INTO subs (subs_name, subs_email, subs_birthday) VALUES ('$name', '$email', '$birthday')");
mysqli_close($con);
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和
mysqli_query($con,"IF NOT EXISTS(SELECT * FROM subs WHERE subs_email='$email')
Begin
INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES ('$name', '$email', '$birthday')
End");
mysqli_close($con);
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但它们都不起作用,我做错了什么?
任何帮助是极大的赞赏!
egg*_*yal 186
如果列尚不存在,请在列上创建UNIQUE约束subs_email:
ALTER TABLE subs ADD UNIQUE (subs_email)
Run Code Online (Sandbox Code Playgroud)用途INSERT ... ON DUPLICATE KEY UPDATE:
INSERT INTO subs
(subs_name, subs_email, subs_birthday)
VALUES
(?, ?, ?)
ON DUPLICATE KEY UPDATE
subs_name = VALUES(subs_name),
subs_birthday = VALUES(subs_birthday)
Run Code Online (Sandbox Code Playgroud)您可以使用UPDATE子句中的VALUES(col_name)函数来引用INSERT的INSERT部分中的列值... ON DUPLICATE KEY UPDATE - dev.mysql.com