Nik*_*han 0 cocoa-touch objective-c nsurl
我需要从服务中获取数据URL.但我无法得到它.可能像空白一样阻止它.我无法理解如何解决它.
NSString *urlString= [NSString
stringWithFormat:@"http://252.249.193.152/Services/User?q=John&p=Browny&r=City Hospital&s=03/13/2013&t=04:00PM&u=ue1f002d-8c8f-4acba75b-8960a6c33bbt&APIKEY=d80d1db7-10d5-4b45-9212-3c699332f2c9"];
NSURL *jsonUrl =[NSURL URLWithString:urlString];
parser = [[NSXMLParser alloc] initWithContentsOfURL:jsonUrl];
[parser setDelegate:self];
[parser setShouldProcessNamespaces:NO];
[parser setShouldReportNamespacePrefixes:NO];
[parser setShouldResolveExternalEntities:NO];
[parser parse];
[parser release];
NSLog(@"%@",array);
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但是我在数组中得到null并且jsonurl正在返回nil.
首先检查你URL,我确定那里的错误,如果你URL的正确,那么使用下面的代码.
NSString *urlString = [NSString stringWithFormat:@"URL_STRING"];
NSURL *jsonUrl = [NSURL URLWithString:[urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
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