C# - 简单或复杂多线程函数的标准代理

Question

C#中是否有标准委托,我只能用于调用.我是否必须为每个必须调用的新函数签名声明一个新委托？

现在我只有那些签名.但是,如果我可以使用本机委托来获得任何复杂的返回和参数,那将是很好的.

public bool isDone()
{...}
public void doStuff()
{...}
public void doMoreStuff(object o)
{...}
public void doEvenMoreStuff(string str)
{...}

// I'm declaring my "custom" delegates like this:
private delegate bool delegate_bool();
private delegate void delegate_void(string line);

// and calling via
if (InvokeRequired)
    Invoke(new delegate_void(doStuff), new object[] { });
else
    {...}

---

编辑:答案似乎是Action <>和Func <>.

if (InvokeRequired)
    return Invoke(new Func<bool>(isDone), new object[] { });
else
    {...}
if (InvokeRequired)
    BeginInvoke(new Action(doStuff), new object[] { });
else
    {...}
if (InvokeRequired)
    BeginInvoke(new Action<string>(doEvenMoreStuff), new object[] { "hello world" });
else
    {...}

Answer 1

你正在寻找Action<*>和Func<*>代表,这正是这样做的.