使用C动态分配struct

Nat*_*han 0 c

我正在尝试分配一个struct数组.当我尝试初始化一个值并在函数中打印值时,一切正常.当我在main中打印相同的值时,我的程序崩溃了.

void getHeader(FILE* fpFile, HEADER *pHead)
{
   //  Local Declaration
   int worker, salesWeek, i;
   PERSON *list;

   //  Statement
   fscanf(fpFile, "%d %d", &worker, &salesWeek);
   list = aloPerson(worker);
   HEADER header = {worker, salesWeek, list};
   pHead = &header;

   return;
}// getHeader


PERSON* aloPerson(int worker)
{
   //  Local Declaration
   PERSON *list;

   //  Statement
   list =(PERSON*)calloc(worker, sizeof(PERSON));
   if(list == NULL)
   {
      MEM_ERROR, exit(103);
   }

   return list;
}// aloPerson
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这是我的结构.

typedef struct
{
int worker;
int weeks;
PERSON *pAry;
}HEADER;
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这是主要的:

int main ( void )
{
//  Local Declaration
FILE* fpFile;
char  nameIn[25];
char *endPro = "end";
HEADER *pHead;

//  Statement
printf("Please select file to to open.\nsales or sales_2: ");
scanf("%s", nameIn);
FLUSH;

do
{
    valiFile(nameIn);
    fpFile = openFile(nameIn);
    getHeader(fpFile, pHead);
    readFile(fpFile, pHead);

    repeat(nameIn);
}
while(strcmp(nameIn, endPro) != 0);


return 0;
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Mah*_*yez 5

我想你需要改变这行代码:

HEADER header = {worker, salesWeek, list};
pHead = &header;
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成为:

HEADER header = {worker, salesWeek, list};
*pHead = header;
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还要确保pHead不为null否则返回错误null参数.如果你想动态,然后使用calloc分配头变量,那么你可以使用你的旧代码.

在你的main函数中确保这一行

HEADER *pHead;
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改为

HEADER *pHead = (HEADER*)calloc(1, sizeof(HEADER));
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也别忘了释放它.