Tyl*_*ler 1 python string function list punctuation
我希望程序让我们说,如果我的word_str是"这是'剑桥大学'".如果单词的长度大于3个字符长,它将保留单词的第一个和最后一个字母并加扰单词的内部.我的问题是,它错误地在单词的开头或结尾处用标点符号洗牌.我需要它进行随机播放,以便标点符号保留在正确的索引中,然后保留单词的第一个和最后一个字母,并在最后添加标点符号的内容中随机播放(如果有的话).有任何想法吗?
def scramble_word(word_str):
char = ".,!?';:"
import random
if len(word_str) <= 3:
return word_str + ' '
else:
word_str = word_str.strip(char)
word_str = list(word_str)
scramble = word_str[1:-1]
random.shuffle(scramble)
scramble = ''.join(scramble)
word_str = ''.join(word_str)
new_word = word_str[0] + scramble + word_str[-1]
return new_word + ' '
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使用正则表达式:
import random
import re
random.seed(1234) #remove this in production, just for replication of my results
def shuffle_word(m):
word = m.group()
inner = ''.join(random.sample(word[1:-1], len(word) - 2))
return '%s%s%s' % (word[0], inner, word[-1])
s = """This is 'Cambridge University' for example."""
print re.sub(r'\b\w{3}\w+\b', shuffle_word, s)
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哪个打印
Tihs is 'Cadibrgme Uinrtvsiey' for exlampe.
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re.sub 允许您传递一个函数(接受正则表达式匹配对象)而不是替换字符串.
from StringIO import StringIO
def shuffle_word(m):
inner = ''.join(random.sample(m[1:-1], len(m) - 2))
return '%s%s%s' % (m[0], inner, m[-1])
def scramble(text)
sio = StringIO(text)
accum = []
start = None
while sio.tell() < sio.len:
char = sio.read(1)
if start is None:
if char.isalnum():
start = sio.tell() - 1
else:
accum.append(char)
elif not char.isalnum():
end = sio.tell() - 1
sio.seek(start)
accum.append(shuffle_word(sio.read(end - start)))
print accum[-1]
start = None
else:
if start is not None:
sio.seek(start)
word = sio.read()
if len(word) > 3:
accum.append(shuffle_word(sio.read()))
else:
accum.append(word)
return ''.join(accum)
s = """This is 'Cambridge University' for example."""
print scramble(s)
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