textPersonName和textPassword之间的比较

Question

我的活动是一个简单的登录活动,其中(仅限测试)如果用户名&&密码相等则返回true,否则返回false.

但它总是返回虚假.

即使我转换toString();示例:

String a=(txtUserName.getText().toString() == txtPassword.getText().toString()) ? "equal" : "Nequal";

完整代码:

public void onCreate(Bundle savedInstanceState) {
  super.onCreate(savedInstanceState);
  setContentView(R.layout.activity_login);
  txtUserName = (EditText) this.findViewById(R.id.txtUname);
  txtPassword = (EditText) this.findViewById(R.id.txtPwd);
  btnLogin = (Button) this.findViewById(R.id.btnLogin);
  btnLogin.setOnClickListener(new OnClickListener() {
    @Override


      public void onClick(View v) {
      Toast.makeText(LoginActivity.this,txtUserName.getText(),Toast.LENGTH_LONG).show();
      Toast.makeText(LoginActivity.this,"Just for separate", Toast.LENGTH_LONG).show();
      Toast.makeText(LoginActivity.this,txtPassword.getText(), Toast.LENGTH_LONG).show();

      String a=(txtUserName.getText() == txtPassword.getText()) ? "equal" : "Nequal";

      Toast.makeText(LoginActivity.this, a, Toast.LENGTH_LONG).show();

    }

  });
}  

Answer 1

使用

  String a=(txtUserName.getText().toString().equals(txtPassword.getText().toString()))

你正在做的方式不是将字符串等同而是将字符串对象等同起来.始终使用String.equals()方法进行字符串比较.

Java String.equals与==