将值传递给jquery对话框表单

Question

我需要一个对话框窗口来弹出一个表单并将值传递给此表单.我尝试了几种解决这个问题的方法,但我无法这样做.我一直在搜索,似乎什么都没有用.

这是我最近的尝试:

  var message="variable";

 .click(function() {
 $( "#dialog-form" ).dialog( "open" );
 $('<input>').attr({
    type: 'text',
    id: 'hidden-input",
    value: message,
    name: 'bar'
 }).appendTo("#dialog-form");

如果我把追加放在对话框内弹出停止工作(我想我不知道如何正确地做到这一点)

Answer 1

我完全使用脚本进行对话处理(我认为它更干净):

http://jsfiddle.net/fE6q2/

HTML:

Default firstname:<br>
<input type='text' id="default_firstname"/>
<br><br>
<button onclick='on_create_form_clicked()'>create form</button>

JavaScript的:

function on_create_form_clicked()
{
    var html =
       "<div>" +
          "Firstname:<br>" +
          "<input type='text' class='firstname'/>" +
          "<br/><br/>" +
          "Lastname:<br>" +
          "<input type='text' class='lastname'/>" +
          "<br/><br/>" +
          "<button class='ok'>ok</button>" +    
       "</div>";

    var div = $(html);

    var default_firstname = $('#default_firstname').val();
    div.find('.firstname').val(default_firstname);        

    div.find('.ok').click(function()
    {
        div.dialog('close');

        var firstname = div.find('.firstname').val();
        var lastname = div.find('.lastname').val();

        alert("firstname was " + firstname
            + " and lastname was " + lastname);        
    });

    div.dialog(
    {
        title:"Enter firstname and lastname",
        close: destroy_this_dialog
    });
}

function destroy_this_dialog(event, ui)
{
  $(this).dialog("destroy");
  $(this).remove();
}

Answer 2

我想你正在寻找这样的东西:

<script>
$(function(){
   var message = "variable";

   $("#showDialog").click(function() {
      $("#hidden-input").val(message);

      $("#dialogForm").dialog("open");
   });
});
</script>

<button id="showDialog">Show Dialog</button>

<div id="dialogForm">
<input type="text" id="hidden-input" name="bar"/>
</div>