Spring MVC - 如何使用控制器方法更新模型对象的属性？

Question

使用Spring MVC 3.0,我正在开发一个具有基本CRUD操作的成员管理系统,并且我的控制器出现问题.

我无法使用Controller方法更新成员记录.我有方法显示和处理我的"添加会员"表单,另一个显示我的"编辑会员"表单,他们都工作正常.

这是我的控制器:

@Controller
public class MemberController {

private MemberService memberService;

@Inject
public MemberController(MemberService memberService) {
    this.memberService = memberService;
}

// Show member list
@RequestMapping(value = "/members/list", method = RequestMethod.GET)
public String showMemberList(Map<String, Object> model) {

    model.put("members", memberService.getAllMembers());

    return "members/list";
}

// Display add member form
@RequestMapping(value = "/members/add", method = RequestMethod.GET)
public String showAddMemberForm(Model model) {

    model.addAttribute(new Member());

    return "members/add";
}

// Process add member form
@RequestMapping(value = "/members/add", method = RequestMethod.POST)
public String addMember(Member member) {

    memberService.addMember(member);

    return "redirect:list";
}

// Display edit member form
@RequestMapping(value = "/members/edit/{id}", method = RequestMethod.GET)
public String showEditMemberForm(Model model, @PathVariable int id) {

    String idAsString = Integer.toString(id);
    model.addAttribute("member", memberService.getMemberById(idAsString));

    return "members/edit/{id}";
}

// Process edit member form
@RequestMapping(value = "/members/edit/{id}", method = RequestMethod.POST)
public String updateMember(@PathVariable int id, 
        HttpServletRequest request, Member member) {

    // Uncommenting the next line of code sets the member objects forename attribute
    // to "test forename"
    // member.setForename("test forename");

    // Uncommenting the next line of code gives the following error:
    // HTTP Status 405 - Request method 'POST' not supported
    //member.setSurname(request.getParameter("surname"));

    memberService.updateMember(member);

    return "redirect:/members/list";
}

}

这是我的更新方法:

public void update(Member member) {
    jdbcTemplate.update(
            "UPDATE members SET forename=?, surname=?, address1=?, address1=?, "
                    + "city=?, postcode=? WHERE memberId=?",
            member.getForename(), member.getSurname(),
            member.getAddress1(), member.getAddress2(), member.getCity(),
            member.getPostcode(), member.getId());
}

这是我的编辑成员JSP表单:

<sf:form method="POST" modelAttribute="member"
    enctype="multipart/form-data" action="/members/edit/${member.id}">
    <fieldset>
        <table cellspacing="0">
            <tr>
                <th><label for="member_id">Id:</label></th>
                <td><sf:input path="id" size="15" id="member_id" /></td>
            </tr>
            <tr>
                <th><label for="member_forename">Forename:</label></th>
                <td><sf:input path="forename" size="15" id="member_forename" /></td>
            </tr>
            <tr>
                <th><label for="member_surname">Surname:</label></th>
                <td><sf:input path="surname" size="15" id="member_surname" /></td>
            </tr>
            <tr>
                <th><label for="member_address1">Address 1:</label></th>
                <td><sf:input path="address1" size="15" id="member_address1" />
                </td>
            </tr>
            <tr>
                <th><label for="member_address2">Address 2:</label></th>
                <td><sf:input path="address2" size="15" id="member_address2" />
                </td>
            </tr>
            <tr>
                <th><label for="member_city">City:</label></th>
                <td><sf:input path="city" size="15" id="member_city" /></td>
            </tr>
            <tr>
                <th><label for="member_postcode">Postcode:</label></th>
                <td><sf:input path="postcode" size="15" id="member_postcode" />
                </td>
            </tr>

        </table>
        <input type="submit" value="Update" />
    </fieldset>
</sf:form>

因为"member.setForename('测试用的名字’)"在我的控制器代码将测试字符串,我想我可以使用从形式发布到设置atrributes如下参数:

'member.setSurname(用request.getParameter( "姓"))'

但这会导致HTTP 405错误.使用Firebug,我已经确认'编辑成员'表单正在发布'forename','surname','address1'等参数,所以我无法弄清楚为什么我不能将它们从请求中删除.

任何帮助将非常感激,因为我已经在这2天,并围绕圈子.

Answer 1

@RequestMapping(value = "/members/edit/{id}", method = RequestMethod.POST)
public String updateMember(@PathVariable int id, 
    HttpServletRequest request,@ModelAttribute("member") Member member) {

//希望你的会员服务看起来很相似

public void edit(Member member) {
logger.debug("Editing existing member");

// Retrieve session from Hibernate, if you are using hibernate
Session session = sessionFactory.getCurrentSession();

// Retrieve existing member via id
Member existingMember = (Member) session.get(Member.class, member.getId());

// Assign updated values to this member
existingMember.setForeName(member.getForeName());
existingMember.setSurName(member.getSurName());
...
...
existingMember.setPostcode(member.getPostcode());

// Save updates
session.save(existingMember);

}

Answer 2

@RequestMapping(value = "/members/edit/{id}", method = RequestMethod.POST)
public String updateMember(@PathVariable int id, 
        HttpServletRequest request,@ModelAttribute("member") Member member) {

添加@ModelAttribute在 之前Member。然后这个实例将拥有所有编辑。所以你不需要通过设置新值request.getParameter。只需将此实例保存在数据库中即可。