以编程方式创建TableLayout

Question

我正在尝试以编程方式创建TableLayout.它不会起作用.然而,xml文件中的相同布局有效.这就是我所拥有的:

public class MyTable extends TableLayout
{
    public MyTable(Context context) {
        super(context);

        setLayoutParams(new TableLayout.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
        TableRow row = new TableRow(context);
        row.setLayoutParams(new TableRow.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));

        Button b = new Button(getContext());
        b.setText("hello");
        b.setLayoutParams(new LayoutParams(TableRow.LayoutParams.FILL_PARENT, TableRow.LayoutParams.WRAP_CONTENT));
        row.addView(b); 
        addView(row)
    }
}

...

// In main activity:
MyTable table = new MyTable(this);
mainLayout.addView(table);

当我运行它时,我没有崩溃,但没有出现.如果我摆脱TableRow实例,至少该按钮确实显示为TableLayout的直接子项.我究竟做错了什么？

Answer 1

只是为了让答案更清楚:

TableLayout.LayoutParams tableParams = new TableLayout.LayoutParams(TableLayout.LayoutParams.WRAP_CONTENT, TableLayout.LayoutParams.WRAP_CONTENT);
TableRow.LayoutParams rowParams = new TableRow.LayoutParams(TableRow.LayoutParams.WRAP_CONTENT, TableRow.LayoutParams.WRAP_CONTENT);

TableLayout tableLayout = new TableLayout(context);
tableLayout.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT));// assuming the parent view is a LinearLayout

TableRow tableRow = new TableRow(context);
tableRow.setLayoutParams(tableParams);// TableLayout is the parent view

TextView textView = new TextView(context);
textView.setLayoutParams(rowParams);// TableRow is the parent view

tableRow.addView(textView);

说明
调用时setLayoutParams,应该传递LayoutParams父视图

Answer 2

事实证明我需要为布局参数指定TableRowLayout,TableLayout等,否则表格就不会显示!