Java:对String数组进行排序,其字符串表示int

Question

我有String[]阵列喜欢

{"3","2","4","10","11","6","5","8","9","7"}

我想按数字顺序对其进行排序,而不是按字母顺序排序.

如果我使用

Arrays.sort(myarray);

我知道了

{"10","11","2","3","4","5","6","7","8","9"}

代替

{"2","3","4","5","6","7","8","9","10","11"}

Answer 1

尝试自定义Comparator,如下所示:

    Arrays.sort(myarray, new Comparator<String>() {
        @Override
        public int compare(String o1, String o2) {
            return Integer.valueOf(o1).compareTo(Integer.valueOf(o2));
        }
    });

希望你喜欢!

Answer 2

我认为迄今为止将Strings转换为s的最简单和最有效的方法int：

int[] myIntArray = new int[myarray.length];

for (int i = 0; i < myarray.length; i++) {
    myIntArray[i] = Integer.parseInt(myarray[i]);
}

然后对整数数组进行排序。如果您确实需要，您可以随时转换回来：

for (int i = 0; i < myIntArray.length; i++) {
    myarray[i] = "" + myIntArray[i];
}

另一种方法是使用Comparator接口来准确地规定如何比较元素，但这可能相当于将每个String值转换为int无论如何 - 使上述方法更加有效。