从文件中读取矩阵,制作边列表,并将边列表写入文件

sck*_*ott 2 python networkx

这应该很简单,但我无法弄清楚。我只需要

  • 将矩阵从文件读入 Python(该矩阵没有标题/行名称)
  • 将其转换为边缘列表
  • 将边缘列表写入文件

我可以分别执行这些操作,但我不知道如何从导入的矩阵转换为 networkx 模块中的图形对象。如果我能够转换为 networkx 图,那么我可以制作一个边列表并写入文件。

要读入的矩阵示例(保存在 .txt 文件中)

1 0 1 0 1
1 0 1 0 0
1 0 1 0 1
0 0 1 0 0
1 1 1 1 0
1 1 1 0 1
1 0 1 0 0
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War*_*ser 5

这使用 numpy 读取矩阵并将邻接数据转换为边列表。然后它创建一个 networkx Graph,并绘制一个图。

import numpy as np
import networkx as nx
import matplotlib.pyplot as plt


# Load the adjacency matrix into a numpy array.
a = np.loadtxt('matrix.txt', dtype=int)

print "a:"
print a

num_nodes = a.shape[0] + a.shape[1]

# Get the row and column coordinates where the array is 1.
rows, cols = np.where(a == 1)

# We label the nodes corresponding to the rows with integers from 0 to
# a.shape[0]-1, and we label the nodes corresponding to the columns with
# integers from a.shape[0] to a.shape[0] + a.shape[1] - 1.
# Rearranges the list of rows and columns into a list of edge tuples.
edges = zip(rows.tolist(), (cols + a.shape[0]).tolist())
print "U nodes:", np.arange(a.shape[0])
print "V nodes:", np.arange(a.shape[1]) + a.shape[0]
print "edges"
print edges

# Create a Graph object (from the networkx library).
b = nx.Graph()
b.add_nodes_from(range(num_nodes))  # This line not strictly necessry.
b.add_edges_from(edges)

# Draw the graph.  First create positions for each node. Put the U nodes
# on the left (x=1) and the V nodes on the right (x=2).
pos = dict([(k, (1, k - 0.5 * a.shape[0]))
            for k in range(a.shape[0])])
pos.update(dict([(k + a.shape[0], (2, k - 0.5 * a.shape[1]))
                  for k in range(a.shape[1])]))
nx.draw_networkx(b, pos=pos, node_color=(['c'] * a.shape[0]) + (['y'] * a.shape[1]))

plt.axis('off')
plt.show()
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输出:

a:
[[1 0 1 0 1]
 [1 0 1 0 0]
 [1 0 1 0 1]
 [0 0 1 0 0]
 [1 1 1 1 0]
 [1 1 1 0 1]
 [1 0 1 0 0]]
U nodes: [0 1 2 3 4 5 6]
V nodes: [ 7  8  9 10 11]
edges:
[(0, 7), (0, 9), (0, 11), (1, 7), (1, 9), (2, 7), (2, 9), (2, 11), (3, 9), (4, 7), (4, 8), (4, 9), (4, 10), (5, 7), (5, 8), (5, 9), (5, 11), (6, 7), (6, 9)]
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剧情: 二分图