按此按钮时,我正在尝试显示吐司.但是代码不起作用

tMJ*_*tMJ 5 android toast

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);



    Button btn = (Button) findViewById(R.id.button1);
    btn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            EditText text = (EditText)findViewById(R.id.editText1);
            EditText text1 = (EditText)findViewById(R.id.editText2);
            String userid = text.getText().toString();
            String pass = text1.getText().toString();
        Toast.makeText(getBaseContext(),"Entered"+userid+"and password entered is"+pass,Toast.LENGTH_SHORT).show();
        }

    });

}
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代码执行成功,但按下按钮时没有任何反应.当我专注于eclipse中的那一行时,它会说以下内容

"The method makeText(Context, CharSequence, int) in the type Toast is not applicable for the arguments (new 
 View.OnClickListener(){}, String, int)"
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请告诉我我需要做些什么来使它工作

poi*_*oae 18

您必须将当前Context作为第一个参数(而不是getBaseContext())传递.在你的情况下,这是MainActivity.this.

Toast.makeText(MainActivity.this,"Entered"+userid+"and password entered is"+pass,Toast.LENGTH_SHORT).show();
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