TIM*_*MEX 4 python django jquery
假设我有一个AJAX函数:
function callpage{
$.ajax({
method:"get",
url:"/abc/",
data:"x="+3
beforeSend:function() {},
success:function(html){
IF HTTPRESPONSE = "1" , ALERT SUCCESS!
}
});
return false;
}
}
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当我的"View"在Django中执行时,我想返回HttpResponse('1')或'0'.
我怎么知道它是否成功,然后发出警报?
Tom*_*eys 16
典型的工作流程是让服务器将JSON对象作为文本返回,然后在javascript中解释该对象.在您的情况下,您可以从服务器返回文本{"httpresponse":1},或使用python json libary为您生成.
JQuery有一个很好的json-reader(我只是阅读了文档,所以我的例子中可能有错误)
使用Javascript:
$.getJSON("/abc/?x="+3,
function(data){
if (data["HTTPRESPONSE"] == 1)
{
alert("success")
}
});
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Django的
#you might need to easy_install this
import json
def your_view(request):
# You can dump a lot of structured data into a json object, such as
# lists and touples
json_data = json.dumps({"HTTPRESPONSE":1})
# json data is just a JSON string now.
return HttpResponse(json_data, mimetype="application/json")
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Issy建议的另一种观点(可爱,因为它符合DRY原则)
def updates_after_t(request, id):
response = HttpResponse()
response['Content-Type'] = "text/javascript"
response.write(serializers.serialize("json",
TSearch.objects.filter(pk__gt=id)))
return response
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